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anonymous

  • one year ago

HELP ME UNDERSTAND What is the solution for the equation 4x − 10 = 2x? x = ___.

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  1. anonymous
    • one year ago
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    @pooja195 can you help?

  2. pooja195
    • one year ago
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    Do you know what the first step would be?

  3. anonymous
    • one year ago
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    add 10?

  4. pooja195
    • one year ago
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    ok so we have \[\huge~\rm~4x=2x+10\] whats next?

  5. anonymous
    • one year ago
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    divide by 4?

  6. pooja195
    • one year ago
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    not quite we need to subtract the 2x \[\huge~\rm~2x=10\] now we can divide by 2 \[\huge~\rm~\frac{ 2x=10 }{ 2~~=2}\]

  7. anonymous
    • one year ago
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    wouldnt it be x= 2 ?? and what about 4x?

  8. pooja195
    • one year ago
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    We subtracted the 2x from 4x because we need to ISOLATE x \[\huge~\rm~2\div2=?\] \[\huge~\rm10\div 2=?\]

  9. anonymous
    • one year ago
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    x=5?

  10. pooja195
    • one year ago
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    yes :)

  11. anonymous
    • one year ago
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    thanks!

  12. pooja195
    • one year ago
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    :) \(\huge\color{orange}{Welcome~To~OpenStudy}\) Hey there!!! Since you are new here, read this legendary tutorial for new OpenStudiers!! http://goo.gl/5pp1u0 For an visual tutorial look at this! Its amazing :o https://prezi.com/fs3hqdpcopic/an-unofficial-guide-to-openstudy/ Also consider reading the CoC and the T&C http://openstudy.com/code-of-conduct http://openstudy.com/terms-and-conditions

  13. anonymous
    • one year ago
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    do you mind checking my answer for one question?

  14. pooja195
    • one year ago
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    not at all post it :)

  15. anonymous
    • one year ago
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    Henry's rocket is designed to launch to a height of 100 feet in the air. The measurements so far have the launch height (h) varying no more than 4 feet. Which inequality below represents this scenario? |h − 4| less than or equal to 100 |h + 4| greater than or equal to 100 |h − 100| less than or equal to 4< my answer |h + 100| greater than or equal to 4

  16. pooja195
    • one year ago
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    im not sure you may want to make a seperate post for this sorry!

  17. anonymous
    • one year ago
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    its ok, thanks for trying :)

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