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vera_ewing

  • one year ago

Did I write this out correctly?

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  1. vera_ewing
    • one year ago
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    So I wrote: \[\frac{ 1 }{ 3 }m~is~n < \frac{ 1 }{ 2 }m\]

  2. vera_ewing
    • one year ago
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    @jim_thompson5910 Did I write it correctly?

  3. jim_thompson5910
    • one year ago
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    the "is" translates to an equals sign you should have this equation \[\Large \frac{1}{3}m = \frac{1}{2}m - n\]

  4. vera_ewing
    • one year ago
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    So how would I solve? Can I just plug in the answer choices? Or is there a faster, more efficient way?

  5. jim_thompson5910
    • one year ago
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    |dw:1434502471198:dw|

  6. jim_thompson5910
    • one year ago
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    Let's say m was a multiple of 3 that would mean 1/3 times m is some integer |dw:1434502504575:dw|

  7. vera_ewing
    • one year ago
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    \[\frac{ 1 }{ 3 }m - \frac{ 1 }{ 2 }m = -n\]

  8. jim_thompson5910
    • one year ago
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    m & n are integers, so the "-n" portion on the RHS is an integer the 1/2 times m portion must also be an integer to form the entire RHS to be an integer

  9. jim_thompson5910
    • one year ago
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    |dw:1434502575606:dw|

  10. jim_thompson5910
    • one year ago
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    |dw:1434502590368:dw|

  11. jim_thompson5910
    • one year ago
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    so m must be a multiple of 2 and 3

  12. vera_ewing
    • one year ago
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    Ohhh okay! Thanks for explaining that!

  13. jim_thompson5910
    • one year ago
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    np

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