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anonymous
 one year ago
will fan & medal!!!!!!!!!!!!!!
2. A model rocket is launched from the ground with an initial velocity of 288 ft/sec.
c. How long will it take the rocket to reach its maximum height? Show all work in the space provided.
anonymous
 one year ago
will fan & medal!!!!!!!!!!!!!! 2. A model rocket is launched from the ground with an initial velocity of 288 ft/sec. c. How long will it take the rocket to reach its maximum height? Show all work in the space provided.

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.1i am guessing you are supposed to use \[h(t)=16t^2+228t\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1max is at the vertex first coordinate of the vertex is always \[\frac{b}{2a}\] which in your case is \[\frac{288}{2\times (16)}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0d. Assume the model rocket’s parachute failed to deploy and the rocket fell back to the ground. How long would it take the rocket to return to Earth from the time it was launched? Show all work in the space provided.

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1set \[16t^2+288t=0\] and solve for \(t\) takes 3 steps only

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1factors nicely as \[ 16t (t18) = 0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0another way to think about it is to simply take the derivative of the equation 'misty1212' posted which is 32t=288 and t=288/32. to prove this, the second derivative is 32 which is < 0 therefore it is a maximum.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thnx a lot guys really appreciate the help
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