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itsmichelle29

  • one year ago

I give medals to helpers thanks Regan is trying to find the equation of a quadratic that has a focus of (−2, 5) and a directrix of y = 13. Describe to Regan your preferred method for deriving the equation. Make sure you use Regan's situation as a model to help her understand.

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  1. itsmichelle29
    • one year ago
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    can you guys help me plz

  2. anonymous
    • one year ago
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    y = -1/16(x - (-2))^2 +9.

  3. itsmichelle29
    • one year ago
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    I dont understand

  4. itsmichelle29
    • one year ago
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    Describe to Regan your preferred method for deriving the equation. Make sure you use Regan's situation as a model to help her understand. Can you give me this answer

  5. misty1212
    • one year ago
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    HI!!

  6. itsmichelle29
    • one year ago
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    hi omg can you please help me

  7. misty1212
    • one year ago
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    no one likes these conic section questions, but they are not that hard really

  8. misty1212
    • one year ago
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    first off, do you know what the parabola would look like (open right, left, up or down?)

  9. itsmichelle29
    • one year ago
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    Nope

  10. misty1212
    • one year ago
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    hmm that is a problem lets plot the focus and graph the directrix

  11. itsmichelle29
    • one year ago
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    okay

  12. misty1212
    • one year ago
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    |dw:1434503255264:dw|

  13. misty1212
    • one year ago
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    you can see that the focus \((-2,5)\) is BELOW the directrix, which is a horizontal line that means the parabola will open DOWN

  14. itsmichelle29
    • one year ago
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    Ohhh okay

  15. misty1212
    • one year ago
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    the next thing we need to do is find the vertex do you know how to find it ?

  16. itsmichelle29
    • one year ago
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    No ='(

  17. misty1212
    • one year ago
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    it is the point half way between \((-2,5)\) and \(y=13\) what is half way between \(5\) and \(13\)?

  18. itsmichelle29
    • one year ago
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    9

  19. misty1212
    • one year ago
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    right (got logged out somehow)

  20. misty1212
    • one year ago
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    that means the vertex is \((-2,9)\)

  21. misty1212
    • one year ago
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    now we are almost done

  22. itsmichelle29
    • one year ago
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    OKAY

  23. itsmichelle29
    • one year ago
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    so now what ?

  24. misty1212
    • one year ago
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    since the vertex is \((-2,5)\) and it opens down, it will look like \[4p(y-9)=(x+2)^2\] all we need is \(p\) and to note that \(4p\) will be negative since it opens down

  25. misty1212
    • one year ago
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    oops i meant "since the vertex is \((-2,9)\) my mistake

  26. itsmichelle29
    • one year ago
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    no its -2 5

  27. misty1212
    • one year ago
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    to find \(p\) is also easy it is the distance between the focus \((-2,5)\) and the vertex \((-2,9)\)

  28. itsmichelle29
    • one year ago
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    ohhh n.m.

  29. misty1212
    • one year ago
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    how far from \(5\) to \(9\)?

  30. misty1212
    • one year ago
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    did i lose you?

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