shelby1290
  • shelby1290
Determine the radius and the center of the following circles. Round to the nearest tenth. a) x^2 + y^2 = 81 radius= ? center=? b) x^2 + y^2 = 1 radius= ? centre= ?
Mathematics
chestercat
  • chestercat
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jim_thompson5910
  • jim_thompson5910
|dw:1434503664766:dw|
jim_thompson5910
  • jim_thompson5910
the original x and y can be written as (x-0) and (y-0) |dw:1434503681112:dw|
jim_thompson5910
  • jim_thompson5910
81 is the same as 9^2 |dw:1434503731384:dw|

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jim_thompson5910
  • jim_thompson5910
|dw:1434503759321:dw|
jim_thompson5910
  • jim_thompson5910
compare that to \(\Large (x-h)^2 + (y-k)^2 = r^2\) |dw:1434503785488:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1434503824871:dw|
jim_thompson5910
  • jim_thompson5910
Hopefully all that makes sense?
shelby1290
  • shelby1290
@jim_thompson5910 yea it makes sense but which one is the centre?
jim_thompson5910
  • jim_thompson5910
(h,k) is the center r is the radius
jim_thompson5910
  • jim_thompson5910
|dw:1434503924630:dw|
shelby1290
  • shelby1290
alright
shelby1290
  • shelby1290
and for part b you can't square 1 so what do you do ?
jim_thompson5910
  • jim_thompson5910
yes you can, 1 = 1^2
shelby1290
  • shelby1290
ohhh yea
shelby1290
  • shelby1290
i'm going to try part by myself and then you can check it over for me
jim_thompson5910
  • jim_thompson5910
sure
shelby1290
  • shelby1290
|dw:1434504154480:dw|
shelby1290
  • shelby1290
|dw:1434504263508:dw|
shelby1290
  • shelby1290
jim_thompson5910
  • jim_thompson5910
very nice you have the correct steps, center and radius
shelby1290
  • shelby1290
thanks for the help!
jim_thompson5910
  • jim_thompson5910
you're welcome

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