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dessyj1

  • one year ago

NUmber 8

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  1. anonymous
    • one year ago
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    Hi!! What is the Number 8 for?

  2. misty1212
    • one year ago
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    \[\infty\]

  3. dessyj1
    • one year ago
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    \[if \left(\begin{matrix}8-x^2 for -2\le x \le2 \\ x^2 else where,\end{matrix}\right) then \int\limits_{-1}^{3}f(x) dx is a number \between \]

  4. dessyj1
    • one year ago
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    is a number between?* would you like to know the choices?

  5. dessyj1
    • one year ago
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    how would i do this?

  6. dessyj1
    • one year ago
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    ignore number 8

  7. xapproachesinfinity
    • one year ago
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    hmm i see peiewize function and you the area under its curve

  8. dessyj1
    • one year ago
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    it is a peicewise

  9. xapproachesinfinity
    • one year ago
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    what 8 do yu want us to ignore? 8-x^2? this should be part of the funtion

  10. dessyj1
    • one year ago
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    i am talking about the title of the question. that is what you should ignore

  11. xapproachesinfinity
    • one year ago
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    eh soka!

  12. misty1212
    • one year ago
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    \[f(x) = \left\{\begin{array}{rcc} 8-x^2 & \text{if} & -2\leq x\leq 2\\ x^2& \text{otherwise} & \end{array} \right. \] just seeing if i could do it, ignore me

  13. xapproachesinfinity
    • one year ago
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    alright you just do some linearity here see where you should integrate 8-x^2 and x^2

  14. xapproachesinfinity
    • one year ago
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    as you can see from -1<x<2 you can integrate 8-x^2

  15. xapproachesinfinity
    • one year ago
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    the rest 2 to 3 you integrate x^2

  16. xapproachesinfinity
    • one year ago
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    do you get it, or should i write it down?

  17. dessyj1
    • one year ago
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    i know the answer is 8

  18. dessyj1
    • one year ago
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    The question asks for what the answer could be between

  19. xapproachesinfinity
    • one year ago
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    \[\int_{-1}^{3}f(x)dx=\int_{-1}^{2}f(x)dx+\int_{2}^{3}f(x)dx\] \[\int_{-1}^{2}(8-x^2)dx+\int_{2}^{3}x^2dx\]

  20. dessyj1
    • one year ago
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    The choices were a) 0 and 8 b) 8 and 16 c) 16 and 24 d) 24 and 32 e) 32 and 40

  21. xapproachesinfinity
    • one year ago
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    hmm i see so they separated it you just do those two integral separately

  22. xapproachesinfinity
    • one year ago
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    \[\int_{-1}^{2}(8-x^2)dx=?\]

  23. dessyj1
    • one year ago
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    43/3

  24. xapproachesinfinity
    • one year ago
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    really how ?

  25. dessyj1
    • one year ago
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    the integral is 8x-(1/3)x^3

  26. xapproachesinfinity
    • one year ago
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    i found 62/3

  27. dessyj1
    • one year ago
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    i tried it again, it gave me 21

  28. dessyj1
    • one year ago
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    i made an arithmetic mistake.

  29. xapproachesinfinity
    • one year ago
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    yes 21 is good!

  30. xapproachesinfinity
    • one year ago
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    but then it is not in the choices

  31. dessyj1
    • one year ago
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    I believe the answer is B

  32. dessyj1
    • one year ago
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    Earlier,I said the solution to the intergral was 8 and i was wrong

  33. xapproachesinfinity
    • one year ago
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    something is wrong in what you wrote? that way must work

  34. xapproachesinfinity
    • one year ago
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    can you post a snap shot of the problem please

  35. xapproachesinfinity
    • one year ago
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    is the function exately like missy wrote it

  36. xapproachesinfinity
    • one year ago
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    hey yo there?

  37. xapproachesinfinity
    • one year ago
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    ???

  38. xapproachesinfinity
    • one year ago
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    i'm waiting...

  39. dessyj1
    • one year ago
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    sorry, i will do that now

  40. dessyj1
    • one year ago
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  41. xapproachesinfinity
    • one year ago
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    now i got what is those btw mean we need to add those two integrals and see the solution lies btw what two points

  42. xapproachesinfinity
    • one year ago
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    i found 21 +19/3 =82/3 which lies 24<82/3<32

  43. xapproachesinfinity
    • one year ago
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    go with what we found in the first time and add the other integral

  44. xapproachesinfinity
    • one year ago
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    see if you got same as me

  45. xapproachesinfinity
    • one year ago
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    just miss understood the problem

  46. dessyj1
    • one year ago
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    i got 21-(19/3)

  47. xapproachesinfinity
    • one year ago
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    hmm why -19/3?

  48. dessyj1
    • one year ago
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    never mind

  49. dessyj1
    • one year ago
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    we are good.

  50. dessyj1
    • one year ago
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    so D?

  51. xapproachesinfinity
    • one year ago
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    \[\int_{2}^{3}x^2ds=\frac{x^3}{3}=19/3\]

  52. xapproachesinfinity
    • one year ago
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    yes D

  53. dessyj1
    • one year ago
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    Instead of getting the sum of both integrals, I decided to do the difference.

  54. xapproachesinfinity
    • one year ago
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    yeah i see that :)

  55. xapproachesinfinity
    • one year ago
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    alright i think we solved that :)

  56. dessyj1
    • one year ago
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    Arigato!

  57. xapproachesinfinity
    • one year ago
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    No problem :) yakoso

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