- dessyj1

NUmber 8

- jamiebookeater

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

Hi!! What is the Number 8 for?

- misty1212

\[\infty\]

- dessyj1

\[if \left(\begin{matrix}8-x^2 for -2\le x \le2 \\ x^2 else where,\end{matrix}\right) then \int\limits_{-1}^{3}f(x) dx is a number \between \]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- dessyj1

is a number between?*
would you like to know the choices?

- dessyj1

how would i do this?

- dessyj1

ignore number 8

- xapproachesinfinity

hmm i see peiewize function
and you the area under its curve

- dessyj1

it is a peicewise

- xapproachesinfinity

what 8 do yu want us to ignore?
8-x^2?
this should be part of the funtion

- dessyj1

i am talking about the title of the question. that is what you should ignore

- xapproachesinfinity

eh soka!

- misty1212

\[f(x) = \left\{\begin{array}{rcc}
8-x^2 & \text{if} & -2\leq x\leq 2\\
x^2& \text{otherwise} &
\end{array}
\right.
\]
just seeing if i could do it, ignore me

- xapproachesinfinity

alright you just do some linearity here
see where you should integrate 8-x^2
and x^2

- xapproachesinfinity

as you can see from -1

- xapproachesinfinity

the rest 2 to 3 you integrate x^2

- xapproachesinfinity

do you get it, or should i write it down?

- dessyj1

i know the answer is 8

- dessyj1

The question asks for what the answer could be between

- xapproachesinfinity

\[\int_{-1}^{3}f(x)dx=\int_{-1}^{2}f(x)dx+\int_{2}^{3}f(x)dx\]
\[\int_{-1}^{2}(8-x^2)dx+\int_{2}^{3}x^2dx\]

- dessyj1

The choices were a) 0 and 8
b) 8 and 16
c) 16 and 24
d) 24 and 32
e) 32 and 40

- xapproachesinfinity

hmm i see so they separated it
you just do those two integral separately

- xapproachesinfinity

\[\int_{-1}^{2}(8-x^2)dx=?\]

- dessyj1

43/3

- xapproachesinfinity

really how ?

- dessyj1

the integral is 8x-(1/3)x^3

- xapproachesinfinity

i found 62/3

- dessyj1

i tried it again, it gave me 21

- dessyj1

i made an arithmetic mistake.

- xapproachesinfinity

yes 21 is good!

- xapproachesinfinity

but then it is not in the choices

- dessyj1

I believe the answer is B

- dessyj1

Earlier,I said the solution to the intergral was 8 and i was wrong

- xapproachesinfinity

something is wrong in what you wrote?
that way must work

- xapproachesinfinity

can you post a snap shot of the problem please

- xapproachesinfinity

is the function exately like missy wrote it

- xapproachesinfinity

hey yo there?

- xapproachesinfinity

???

- xapproachesinfinity

i'm waiting...

- dessyj1

sorry, i will do that now

- dessyj1

##### 1 Attachment

- xapproachesinfinity

now i got what is those btw mean
we need to add those two integrals and see the solution lies
btw what two points

- xapproachesinfinity

i found 21 +19/3 =82/3
which lies
24<82/3<32

- xapproachesinfinity

go with what we found in the first time
and add the other integral

- xapproachesinfinity

see if you got same as me

- xapproachesinfinity

just miss understood the problem

- dessyj1

i got 21-(19/3)

- xapproachesinfinity

hmm why -19/3?

- dessyj1

never mind

- dessyj1

we are good.

- dessyj1

so D?

- xapproachesinfinity

\[\int_{2}^{3}x^2ds=\frac{x^3}{3}=19/3\]

- xapproachesinfinity

yes D

- dessyj1

Instead of getting the sum of both integrals, I decided to do the difference.

- xapproachesinfinity

yeah i see that :)

- xapproachesinfinity

alright i think we solved that :)

- dessyj1

Arigato!

- xapproachesinfinity

No problem :)
yakoso

Looking for something else?

Not the answer you are looking for? Search for more explanations.