Can someone factor this in two different ways for a medal?

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Can someone factor this in two different ways for a medal?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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9x2 + 3x - 2 = 0 in one method and 3x2 - 10x + 2 = 0 in a different method.
@Ndude1 How long you gonna be typing dude?
the first equation can be factored using completing the square. First divide each term by 9. 1. x^2+1/3x−2/9=0 2. Take half of x term coefficient (1/3) which is 1/6 then square it to get 1/36 3. add to both sides 4. Now the equation looks like: x^2+1/3x+1/36=1/4 5. Now factor this equation to be: 6. (x+16)^2=1/4 7. square root both sides 8. get x+1/6=±√(1/4) 9. x = ±√(1/4)-(1/6) 10. solve for x now which is (1/3 and -2/3)

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Oh my god your actually here to help
For the second equation factor using quadratic formula because it uses difficult irrational numbers: 1. x =−b±sqrt(b^2−4ac)/2a 2. the equation is of the form ax^2+bx+c, therefore plug in values. 3. Looks something like this: x=−(−10)±sqrt((−10)^2(−4)⋅(3)⋅(2))/2⋅3 4. x is : x=10±√76/6
Is that it?
yes
Thank you so much man.

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