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Yes.
Have you learned about the exponential form of the complex number?

It sounds familiar, if I see it I will probably remember

So in this case 14.76/44.29(cis(0.49-1.92))?

Oh wait, nvm

sorry, I added the wrong equation

14.76/3(cis(0.49-1.43))

mmm ya that looks better! :)

So if I simplify this, it is the answer?

4.92(cis(-0.94)) Is a negative acceptable?

But in general, a negative is fine. :o

awesome! Is rectangular form a+bi?

Not for this equation

Just curious

Also, is the complex conjugate of a r(cos(theta)+isin(theta)) r(cos(theta)-isin(theta))?

ah gotcha

But if there was an r, it would stay the same?

do you think I should do \[8^2\]? Or just write 8?

For what? 0_O

oh sorry, for complex conjugate if r=8 for the original

before the complex conjugate

1.43 was tnat supposed to be root2 lol

@xapproachesinfinity yea

hehe that's weird in decimal and it is 1.41 not 1.43

Oh, wait, it isn't

it is just 1.43, not root 2

The problem gave the equation liek that

oh im not thinking that's angle in radians lol

oh kk

Thanks though

as in multiplying theta by 3 and cubing 4

so de movire I think

ya that seems like the way to go :)

awesome :D Thanks for the help!

yay team

good work :)