Determine the value(s) of k such that each trinomial is a perfect square. a) x^2 + 4x + k b) 4x^2 - 12x + k

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Determine the value(s) of k such that each trinomial is a perfect square. a) x^2 + 4x + k b) 4x^2 - 12x + k

Mathematics
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two steps only
what is half of 4?
@misty1212 half of 4 is 2

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Other answers:

what's next?
\[b^2-4ac=0\]
\[4^2-4(1)(k)=0\]
k=?
12?
Try again
4^2-4(1)(k) 16-4k=0 divide both sides by -4 k=-4
is that right?
\[16-4k=0 \\ \\ 16=4k \\ \\ k=?\]
k = 4 oops
thank you
now how about part b
Do the same for the next one \[4x^2 - 12x + k=0 \\ Using \\ ax^2+bx+c=0 \\ \\ b^2-4ac=0\]
\[(-12)^2-4(4)(k)=0\]
-144-16k=0 -144=16k divide both sides by 16 k=-9 ?
\[(-12)^2= (-12)(-12)=12 \times 12=144\]
k=9
oh i see it's because i didn't put (-12)^2 in brackets
thanks for the help though!

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