Help with lengths. Thanks!

- BeccaB003

Help with lengths. Thanks!

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- katieb

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- BeccaB003

##### 1 Attachment

- Nnesha

\[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]

- BeccaB003

I need to calculate the length of NO. I know how to work these problems EXCEPT I don't know whether to use sin cos or tan.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- Nnesha

alright as you can the functions i posted hve 3 variables so
to find NO you should know one angel and one side
so we have to use sin \[\huge\rm sin(60)= \frac{ opposite }{hyp }\]

- Nnesha

let NO=x
so x is the opposite side of angle 60 and hyp is 24 so substitute
\[\huge\rm sin(60)= \frac{ x}{24}\]
solve for x :=)

- BeccaB003

So, in a problem like this, whenever you have the information of one angle and one side you always use sin?

- Nnesha

nope it depends on sides and angles
like which angle and side they gave you

- Nnesha

for this problem we have to apply sin bec
like i said earlier we need one angle and one side
so given is hyp and angle
and we need to find NO which is opposite side of angle that's why sin

- BeccaB003

So, sin 60 = .866 * 24 = 20.785

- Nnesha

mod should be on degree!!

- Nnesha

e*

- xapproachesinfinity

sin60=root3/2
no need to write before simplifying

- Nnesha

yes that's right

- xapproachesinfinity

i meant no decimal before simplifying :)

- BeccaB003

My calculator is on degree. I checked. Also, I need to know How to know whether a problem is sin cos or tan?? I want to be able to know right off from looking at the problem which one I need to use.

- Nnesha

well
if you have 3 variables formula you should know values of 2 variables to find 3rd one |dw:1434509817378:dw|
i need opposite side and given is hyp
so i should apply sin which is equal to opposite over hyp

- BeccaB003

Also, my answer option isn't 20.785 These are the only options I have and they don't make sense when I do the problem:
\[12\sqrt{2}\]
12
\[12\sqrt{3}\]
\[24\sqrt{3}\]

- xapproachesinfinity

it is just convenient that you write roots as they are

- xapproachesinfinity

you see if the answer were written in that form, no decimal
no calculator is needed!

- Nnesha

okay then :D

- Nnesha

it depends on answer choices :=)

- xapproachesinfinity

not really most often radical need to be written as they if we cannot simplify them

- xapproachesinfinity

as they are*

- BeccaB003

I'm confused. I did the problem but it isn't one of the options.... can you convert it??

- xapproachesinfinity

that is why i'm saying that lol
you see
sin60=x/24 ===> x=24sin60=24 root(3)/2=12root(3)

- Nnesha

yes otherwise they should know the unit circle pattrn or at least memorize it

- xapproachesinfinity

12 root(3) is your answer dear :)

- xapproachesinfinity

yeah must have the unit circle :)

- BeccaB003

Also, @Nnesha thank you for your example about recognizing sin, cos, and tan. After I've completed the current problem, can you draw another example like you did and see if I can recognize the correct one; sin, cos, or tan?

- BeccaB003

Thank you! @xapproachesinfinity

- xapproachesinfinity

no problem

- Nnesha

they are not allowed to have unit circle 'n the final exam :=)

- Nnesha

:3

- xapproachesinfinity

i meant they need to know some way or the other not taking it in the exams hahaha

- xapproachesinfinity

i actually memorized them from table lol
but if i forgot any one of them
i use special triangles

- BeccaB003

haha! oh bother..... my exam is gonna be fun. I never learned about a 'unit circle' in my class.....

- Nnesha

^^^^see

- Nnesha

\(\color{blue}{\text{Originally Posted by}}\) @xapproachesinfinity
i actually memorized them from table lol
but if i forgot any one of them
i use special triangles
\(\color{blue}{\text{End of Quote}}\)
same i memorized it 2
no time for 45-45-9- and 30-60-90 theorem :D

- Nnesha

oh forgot about that okay give me a sec

- Nnesha

|dw:1434511171692:dw|
find angle B :=_

- Nnesha

|dw:1434511566103:dw|
or this one :=)

Looking for something else?

Not the answer you are looking for? Search for more explanations.