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BeccaB003

  • one year ago

Help with lengths. Thanks!

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  1. BeccaB003
    • one year ago
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  2. Nnesha
    • one year ago
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    \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]

  3. BeccaB003
    • one year ago
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    I need to calculate the length of NO. I know how to work these problems EXCEPT I don't know whether to use sin cos or tan.

  4. Nnesha
    • one year ago
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    alright as you can the functions i posted hve 3 variables so to find NO you should know one angel and one side so we have to use sin \[\huge\rm sin(60)= \frac{ opposite }{hyp }\]

  5. Nnesha
    • one year ago
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    let NO=x so x is the opposite side of angle 60 and hyp is 24 so substitute \[\huge\rm sin(60)= \frac{ x}{24}\] solve for x :=)

  6. BeccaB003
    • one year ago
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    So, in a problem like this, whenever you have the information of one angle and one side you always use sin?

  7. Nnesha
    • one year ago
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    nope it depends on sides and angles like which angle and side they gave you

  8. Nnesha
    • one year ago
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    for this problem we have to apply sin bec like i said earlier we need one angle and one side so given is hyp and angle and we need to find NO which is opposite side of angle that's why sin

  9. BeccaB003
    • one year ago
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    So, sin 60 = .866 * 24 = 20.785

  10. Nnesha
    • one year ago
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    mod should be on degree!!

  11. Nnesha
    • one year ago
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    e*

  12. xapproachesinfinity
    • one year ago
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    sin60=root3/2 no need to write before simplifying

  13. Nnesha
    • one year ago
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    yes that's right

  14. xapproachesinfinity
    • one year ago
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    i meant no decimal before simplifying :)

  15. BeccaB003
    • one year ago
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    My calculator is on degree. I checked. Also, I need to know How to know whether a problem is sin cos or tan?? I want to be able to know right off from looking at the problem which one I need to use.

  16. Nnesha
    • one year ago
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    well if you have 3 variables formula you should know values of 2 variables to find 3rd one |dw:1434509817378:dw| i need opposite side and given is hyp so i should apply sin which is equal to opposite over hyp

  17. BeccaB003
    • one year ago
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    Also, my answer option isn't 20.785 These are the only options I have and they don't make sense when I do the problem: \[12\sqrt{2}\] 12 \[12\sqrt{3}\] \[24\sqrt{3}\]

  18. xapproachesinfinity
    • one year ago
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    it is just convenient that you write roots as they are

  19. xapproachesinfinity
    • one year ago
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    you see if the answer were written in that form, no decimal no calculator is needed!

  20. Nnesha
    • one year ago
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    okay then :D

  21. Nnesha
    • one year ago
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    it depends on answer choices :=)

  22. xapproachesinfinity
    • one year ago
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    not really most often radical need to be written as they if we cannot simplify them

  23. xapproachesinfinity
    • one year ago
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    as they are*

  24. BeccaB003
    • one year ago
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    I'm confused. I did the problem but it isn't one of the options.... can you convert it??

  25. xapproachesinfinity
    • one year ago
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    that is why i'm saying that lol you see sin60=x/24 ===> x=24sin60=24 root(3)/2=12root(3)

  26. Nnesha
    • one year ago
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    yes otherwise they should know the unit circle pattrn or at least memorize it

  27. xapproachesinfinity
    • one year ago
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    12 root(3) is your answer dear :)

  28. xapproachesinfinity
    • one year ago
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    yeah must have the unit circle :)

  29. BeccaB003
    • one year ago
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    Also, @Nnesha thank you for your example about recognizing sin, cos, and tan. After I've completed the current problem, can you draw another example like you did and see if I can recognize the correct one; sin, cos, or tan?

  30. BeccaB003
    • one year ago
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    Thank you! @xapproachesinfinity

  31. xapproachesinfinity
    • one year ago
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    no problem

  32. Nnesha
    • one year ago
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    they are not allowed to have unit circle 'n the final exam :=)

  33. Nnesha
    • one year ago
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    :3

  34. xapproachesinfinity
    • one year ago
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    i meant they need to know some way or the other not taking it in the exams hahaha

  35. xapproachesinfinity
    • one year ago
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    i actually memorized them from table lol but if i forgot any one of them i use special triangles

  36. BeccaB003
    • one year ago
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    haha! oh bother..... my exam is gonna be fun. I never learned about a 'unit circle' in my class.....

  37. Nnesha
    • one year ago
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    ^^^^see

  38. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @xapproachesinfinity i actually memorized them from table lol but if i forgot any one of them i use special triangles \(\color{blue}{\text{End of Quote}}\) same i memorized it 2 no time for 45-45-9- and 30-60-90 theorem :D

  39. Nnesha
    • one year ago
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    oh forgot about that okay give me a sec

  40. Nnesha
    • one year ago
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    |dw:1434511171692:dw| find angle B :=_

  41. Nnesha
    • one year ago
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    |dw:1434511566103:dw| or this one :=)

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