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## anonymous one year ago Help with discrete mathematics please???? Find the 6th term of a geometric sequence with t1 = 7 and t9 = 45,927.

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1. anonymous

the 6th term hmmm

2. anonymous

Ay can some please help me pleaseeee its like no one wants to help me

3. anonymous

lol

4. anonymous
5. anonymous

The formula for the nth term of a geometric sequence is $t _{n}=t _{1}r ^{n-1}$ Plug in and solve for r $t _{9}=t _{1}r ^{9-1}$ $45927=7r ^{8}$

6. anonymous

there is your help :P

7. anonymous

Then once you have r, go back and use the same formula to find t6

8. anonymous

The formula for the nth term of a geometric sequence is tn=t1rn−1 Plug in and solve for r t9=t1r9−1 45927=7r8

9. anonymous

lol

10. anonymous

cool

11. anonymous

byes

12. anonymous

R=3 so I got 6237. Is that correct?

13. anonymous

r = 3 is right, but not 6237. What did you use for the exponent when finding t6?

14. anonymous

$t _{6}=7\times3^{6-1}$ right?

15. anonymous

yes. what did you do next?

16. anonymous

$t _{6}=7\times3^{5}$

17. anonymous

so you should have 7*243

18. anonymous

Okay I got 1701 this time

19. anonymous

yep, that's it!

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