anonymous
  • anonymous
Help with discrete mathematics please???? Find the 6th term of a geometric sequence with t1 = 7 and t9 = 45,927.
Mathematics
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
the 6th term hmmm
anonymous
  • anonymous
Ay can some please help me pleaseeee its like no one wants to help me
anonymous
  • anonymous
lol

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anonymous
  • anonymous
The formula for the nth term of a geometric sequence is \[t _{n}=t _{1}r ^{n-1}\] Plug in and solve for r \[t _{9}=t _{1}r ^{9-1}\] \[45927=7r ^{8}\]
anonymous
  • anonymous
there is your help :P
anonymous
  • anonymous
Then once you have r, go back and use the same formula to find t6
anonymous
  • anonymous
The formula for the nth term of a geometric sequence is tn=t1rn−1 Plug in and solve for r t9=t1r9−1 45927=7r8
anonymous
  • anonymous
lol
anonymous
  • anonymous
cool
anonymous
  • anonymous
byes
anonymous
  • anonymous
R=3 so I got 6237. Is that correct?
anonymous
  • anonymous
r = 3 is right, but not 6237. What did you use for the exponent when finding t6?
anonymous
  • anonymous
\[t _{6}=7\times3^{6-1} \] right?
anonymous
  • anonymous
yes. what did you do next?
anonymous
  • anonymous
\[t _{6}=7\times3^{5}\]
anonymous
  • anonymous
so you should have 7*243
anonymous
  • anonymous
Okay I got 1701 this time
anonymous
  • anonymous
yep, that's it!

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