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anonymous

  • one year ago

Help with discrete mathematics please???? Find the 6th term of a geometric sequence with t1 = 7 and t9 = 45,927.

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  1. anonymous
    • one year ago
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    the 6th term hmmm

  2. anonymous
    • one year ago
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    Ay can some please help me pleaseeee its like no one wants to help me

  3. anonymous
    • one year ago
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    lol

  4. anonymous
    • one year ago
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    http://openstudy.com/study#/updates/5580ddbbe4b0e4e582ab20cf

  5. anonymous
    • one year ago
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    The formula for the nth term of a geometric sequence is \[t _{n}=t _{1}r ^{n-1}\] Plug in and solve for r \[t _{9}=t _{1}r ^{9-1}\] \[45927=7r ^{8}\]

  6. anonymous
    • one year ago
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    there is your help :P

  7. anonymous
    • one year ago
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    Then once you have r, go back and use the same formula to find t6

  8. anonymous
    • one year ago
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    The formula for the nth term of a geometric sequence is tn=t1rn−1 Plug in and solve for r t9=t1r9−1 45927=7r8

  9. anonymous
    • one year ago
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    lol

  10. anonymous
    • one year ago
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    cool

  11. anonymous
    • one year ago
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    byes

  12. anonymous
    • one year ago
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    R=3 so I got 6237. Is that correct?

  13. anonymous
    • one year ago
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    r = 3 is right, but not 6237. What did you use for the exponent when finding t6?

  14. anonymous
    • one year ago
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    \[t _{6}=7\times3^{6-1} \] right?

  15. anonymous
    • one year ago
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    yes. what did you do next?

  16. anonymous
    • one year ago
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    \[t _{6}=7\times3^{5}\]

  17. anonymous
    • one year ago
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    so you should have 7*243

  18. anonymous
    • one year ago
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    Okay I got 1701 this time

  19. anonymous
    • one year ago
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    yep, that's it!

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spraguer (Moderator)
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