## anonymous one year ago Help with discrete mathematics please???? Find the 6th term of a geometric sequence with t1 = 7 and t9 = 45,927.

1. anonymous

the 6th term hmmm

2. anonymous

3. anonymous

lol

4. anonymous
5. anonymous

The formula for the nth term of a geometric sequence is $t _{n}=t _{1}r ^{n-1}$ Plug in and solve for r $t _{9}=t _{1}r ^{9-1}$ $45927=7r ^{8}$

6. anonymous

7. anonymous

Then once you have r, go back and use the same formula to find t6

8. anonymous

The formula for the nth term of a geometric sequence is tn=t1rn−1 Plug in and solve for r t9=t1r9−1 45927=7r8

9. anonymous

lol

10. anonymous

cool

11. anonymous

byes

12. anonymous

R=3 so I got 6237. Is that correct?

13. anonymous

r = 3 is right, but not 6237. What did you use for the exponent when finding t6?

14. anonymous

$t _{6}=7\times3^{6-1}$ right?

15. anonymous

yes. what did you do next?

16. anonymous

$t _{6}=7\times3^{5}$

17. anonymous

so you should have 7*243

18. anonymous

Okay I got 1701 this time

19. anonymous

yep, that's it!