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anonymous

  • one year ago

how would you solve a matrix if there is a zero underneath the pivot position?

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  1. UsukiDoll
    • one year ago
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    can you give an example? I know there are row operations 1. you can swap rows 2. you can multiply a row by a number 3. you can add 2 rows to create a new row that will replace the one of the old rows.

  2. UsukiDoll
    • one year ago
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    that's just REF - row echelon form... if you want RREF (reduce row echelon form) you must have 0's above and below the 1 [similar to an identity matrix]

  3. anonymous
    • one year ago
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    k example: row 1: 1 5 7 9 row 2: 0 4 1 7 row 3: 2 -2 11 -3

  4. anonymous
    • one year ago
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    nvm got it but thanks

  5. UsukiDoll
    • one year ago
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    |dw:1434517367302:dw| that 0 isn't doing anything wrong... as long as you don't have a 0 in the main diagonal...which breaks one of the rules... you must have a 1 on the top left corner

  6. UsukiDoll
    • one year ago
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    and then the 1 is shifted down and to the right.. your main diagonal is 1 4 11.

  7. UsukiDoll
    • one year ago
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    |dw:1434517479026:dw| you just need to do some row operations to have every digit below the main diagonal 0.

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