What does 11% and 63% actually mean when we study the phase diagram for a two component system made up of phenol and water?
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Starting at the point a, equivalent to a system containing 100% water (pure water) at 50oC, the addition of known increments of phenol to a fixed weight of water, the whole being maintained at 50oC, will result in the formation of a single liquid phase until the point b is reached, at which a minute amount of a second phase appears.
As we prepare mixtures containing increasing quantities of phenol, that is, as we proceed across the diagram from point b to point c, we form systems in which the amount of the phenol-rich phase continually increases. At the same time, the amount of the water-rich phases decreases. Once the total concentration of phenol exceeds 63%, at 50oC, a single phenol-rich liquid phase is formed. The maximum temperature at which the two-phase region exists is termed the critical temperature.