## anonymous one year ago Which of the following represents the greatest energy transition from a higher energy level to a lower one? A. emission of a red photon of 770 nm B. emission of a green photon of 550 nm C. emission of a yellow photon of 590 nm D. emission of a blue photon of 450 nm

1. Michele_Laino

here we have to compute four energies, namely we have to apply this formula: $E = \frac{{hc}}{\lambda }$

2. anonymous

ok!

3. Michele_Laino

so case red photon: $E = \frac{{hc}}{\lambda } = \frac{{6.62 \times {{10}^{ - 34}}3 \times {{10}^8}}}{{770 \times {{10}^{ - 9}}}} = ...joules$

4. anonymous

i am confused... what does this mean? 10^-34 3 ?

5. Michele_Laino

oops.. sorry: $E = \frac{{hc}}{\lambda } = \frac{{6.62 \times {{10}^{ - 34}} \times 3 \times {{10}^8}}}{{770 \times {{10}^{ - 9}}}} = ...joules$

6. anonymous

oh! okie! so we get 2.579E-19

7. Michele_Laino

that's right!

8. anonymous

does that mean choice A is our soluition?

9. Michele_Laino

no, we have to to the same computation for other wavelength. case green photon: $E = \frac{{hc}}{\lambda } = \frac{{6.62 \times {{10}^{ - 34}} \times 3 \times {{10}^8}}}{{550 \times {{10}^{ - 9}}}} = ...joules$

10. anonymous

ok! so we get 3.61E-19

11. Michele_Laino

that's right!

12. Michele_Laino

case yellow photon: $E = \frac{{hc}}{\lambda } = \frac{{6.62 \times {{10}^{ - 34}} \times 3 \times {{10}^8}}}{{590 \times {{10}^{ - 9}}}} = ...joules$

13. anonymous

and we get 3.366E-19!

14. Michele_Laino

that's right!

15. Michele_Laino

finally, case blue photon: $E = \frac{{hc}}{\lambda } = \frac{{6.62 \times {{10}^{ - 34}} \times 3 \times {{10}^8}}}{{450 \times {{10}^{ - 9}}}} = ...joules$

16. anonymous

4.42E-19!

17. Michele_Laino

that's right!

18. Michele_Laino

reassuming, we have these subsequent energies: 2.579E-19 J, 3.61E-19 J, 3.366E-19 J, 4.42E-19 J. which is the greatest one?

19. anonymous

the last! so our solution is choice D?

20. anonymous

oh wait oops sorry it is the first, right? so chocie A is our solution?

21. Michele_Laino

I think that 4.42 is greater than 2.579

22. anonymous

but it is negative?

23. anonymous

E-19? :/

24. Michele_Laino

that is an exponential, all our energies have 10^(-19) as exponential

25. anonymous

oh so our solution is still choice D?

26. Michele_Laino

yes! that's right!

27. anonymous

yay! thanks:)

28. Michele_Laino

:)