A mixture of .150 moles of C is reacted with .117 moles of O2 in a sealed, 10.0 L vessel at 500K, producing a mixture of CO and CO2. The total pressure is .640 atm. What is the partial pressure of CO?
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@dan815 can you help?
150 moles of C is reacted with .117 moles of O2
Let CO = moles CO formed and CO2 = moles CO2 formed
CO + CO2 = .150, by conserving carbon atoms
CO + 2CO2 = .117 x 2 = .234, by conserving oxygen atoms.
Two linear equations in two unknowns you can solve.
Once you know moles CO you just PV = nRT ---> P = nRT/V; just ignore CO2 as you want partial pressure of CO only
Actually, this problem is overspecified, ie has more information than is required to precisely define it [and the problem can be that the data are not consistent]
So by the above method use CO2 to find the partial pressure of CO2 and add it to that of CO and see if you get .640 atm; if you do not, then the data are inconsistent. CO and CO2 will be pretty ideal under those conditions.