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jessiegonzales

  • one year ago

MEDAL!!!! 6. Insert <,><or= to make the sentence true. 3/4 ? 4/7 A. > B. < C. =

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  1. jessiegonzales
    • one year ago
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    @nincompoop

  2. jessiegonzales
    • one year ago
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    @zepdrix

  3. zepdrix
    • one year ago
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    Hmm the bottoms are different :O Makes them difficult to compare. Let's find the `least common multiple` of 4 and 7.

  4. jessiegonzales
    • one year ago
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    least common multiple is 1?

  5. zepdrix
    • one year ago
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    no no, thats the `greatest common factor` :)

  6. zepdrix
    • one year ago
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    if we count by 4's and count by 7's, when do they meet? :)

  7. jessiegonzales
    • one year ago
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    28

  8. zepdrix
    • one year ago
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    4, 8, 12, 16, 20, 24, 28 7, 14, 21, 28 28 ah good!

  9. zepdrix
    • one year ago
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    So we want a bottom of 28. \[\Large\rm \frac{3}{4}\cdot\color{royalblue}{\frac{7}{7}}\]See how this guy already has a 4 in the bottom? :d so we gotta give him a 7, ya?

  10. jessiegonzales
    • one year ago
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    i see

  11. jessiegonzales
    • one year ago
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    so i mulitpy 3 and 4? 21/28

  12. zepdrix
    • one year ago
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    mmm ok looks good :d how bout the other fraction?

  13. jessiegonzales
    • one year ago
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    21/49

  14. zepdrix
    • one year ago
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    \[\Large\rm \frac{4}{7}\cdot\color{royalblue}{\frac{?}{?}}\]

  15. zepdrix
    • one year ago
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    Hmm this bottom already has a 7. I don't think we wanna give him another 7 in order to get to 28.

  16. jessiegonzales
    • one year ago
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    7/3

  17. zepdrix
    • one year ago
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    So we actually wanna give him a 4, ya?\[\Large\rm \frac{4}{7}\cdot\color{royalblue}{\frac{4}{4}}\]Because the 7 times 4 will give us that 28 that we were looking for.

  18. jessiegonzales
    • one year ago
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    ok

  19. zepdrix
    • one year ago
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    So what do you get for that second fraction? :) Again, multiply top with top, bottom with bottom.

  20. jessiegonzales
    • one year ago
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    16/28

  21. anonymous
    • one year ago
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    its B

  22. anonymous
    • one year ago
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    i think

  23. zepdrix
    • one year ago
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    Ok good, So instead of comparing \(\Large\rm \frac{3}{4}\) and \(\Large\rm \frac{4}{7}\) we can get a common denominator and compare \(\Large\rm \frac{21}{28}\) and \(\Large\rm \frac{16}{28}\)

  24. jessiegonzales
    • one year ago
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    A~

  25. jessiegonzales
    • one year ago
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    >

  26. zepdrix
    • one year ago
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    the first one is bigger? yay good job \c:/

  27. jessiegonzales
    • one year ago
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    thankyou <3

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