MEDAL!!!! 6. Insert <,> B. < C. =

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Hmm the bottoms are different :O Makes them difficult to compare. Let's find the `least common multiple` of 4 and 7.

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Other answers:

least common multiple is 1?
no no, thats the `greatest common factor` :)
if we count by 4's and count by 7's, when do they meet? :)
28
4, 8, 12, 16, 20, 24, 28 7, 14, 21, 28 28 ah good!
So we want a bottom of 28. \[\Large\rm \frac{3}{4}\cdot\color{royalblue}{\frac{7}{7}}\]See how this guy already has a 4 in the bottom? :d so we gotta give him a 7, ya?
i see
so i mulitpy 3 and 4? 21/28
mmm ok looks good :d how bout the other fraction?
21/49
\[\Large\rm \frac{4}{7}\cdot\color{royalblue}{\frac{?}{?}}\]
Hmm this bottom already has a 7. I don't think we wanna give him another 7 in order to get to 28.
7/3
So we actually wanna give him a 4, ya?\[\Large\rm \frac{4}{7}\cdot\color{royalblue}{\frac{4}{4}}\]Because the 7 times 4 will give us that 28 that we were looking for.
ok
So what do you get for that second fraction? :) Again, multiply top with top, bottom with bottom.
16/28
its B
i think
Ok good, So instead of comparing \(\Large\rm \frac{3}{4}\) and \(\Large\rm \frac{4}{7}\) we can get a common denominator and compare \(\Large\rm \frac{21}{28}\) and \(\Large\rm \frac{16}{28}\)
A~
>
the first one is bigger? yay good job \c:/
thankyou <3

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