## jessiegonzales one year ago MEDAL!!!! 6. Insert <,><or= to make the sentence true. 3/4 ? 4/7 A. > B. < C. =

1. jessiegonzales

@nincompoop

2. jessiegonzales

@zepdrix

3. zepdrix

Hmm the bottoms are different :O Makes them difficult to compare. Let's find the least common multiple of 4 and 7.

4. jessiegonzales

least common multiple is 1?

5. zepdrix

no no, thats the greatest common factor :)

6. zepdrix

if we count by 4's and count by 7's, when do they meet? :)

7. jessiegonzales

28

8. zepdrix

4, 8, 12, 16, 20, 24, 28 7, 14, 21, 28 28 ah good!

9. zepdrix

So we want a bottom of 28. $\Large\rm \frac{3}{4}\cdot\color{royalblue}{\frac{7}{7}}$See how this guy already has a 4 in the bottom? :d so we gotta give him a 7, ya?

10. jessiegonzales

i see

11. jessiegonzales

so i mulitpy 3 and 4? 21/28

12. zepdrix

mmm ok looks good :d how bout the other fraction?

13. jessiegonzales

21/49

14. zepdrix

$\Large\rm \frac{4}{7}\cdot\color{royalblue}{\frac{?}{?}}$

15. zepdrix

Hmm this bottom already has a 7. I don't think we wanna give him another 7 in order to get to 28.

16. jessiegonzales

7/3

17. zepdrix

So we actually wanna give him a 4, ya?$\Large\rm \frac{4}{7}\cdot\color{royalblue}{\frac{4}{4}}$Because the 7 times 4 will give us that 28 that we were looking for.

18. jessiegonzales

ok

19. zepdrix

So what do you get for that second fraction? :) Again, multiply top with top, bottom with bottom.

20. jessiegonzales

16/28

21. anonymous

its B

22. anonymous

i think

23. zepdrix

Ok good, So instead of comparing $$\Large\rm \frac{3}{4}$$ and $$\Large\rm \frac{4}{7}$$ we can get a common denominator and compare $$\Large\rm \frac{21}{28}$$ and $$\Large\rm \frac{16}{28}$$

24. jessiegonzales

A~

25. jessiegonzales

>

26. zepdrix

the first one is bigger? yay good job \c:/

27. jessiegonzales

thankyou <3