kanwal32 one year ago Easy capacitance doubt

1. kanwal32

|dw:1434537935776:dw|

2. kanwal32

what will be the equivalent capacitance and why we will take the two in series @Michele_Laino

3. kanwal32

@IrishBoy123

4. kanwal32

5. IrishBoy123

confused. is this not 3 in series or is circuit incomplete?

6. kanwal32

are they three in series

7. kanwal32

how

8. kanwal32

@Michele_Laino

9. kanwal32

should i give any other example to clear my doubt

10. kanwal32

@Michele_Laino

11. kanwal32

|dw:1434539076748:dw|

12. kanwal32

why 2 and 3 are in series and not 1 and 2

13. IrishBoy123

the draw function seems to have disappeared from the user interface. i can't draw anymore.

14. Michele_Laino

since we can rewrite your circuit as follows: |dw:1434539474858:dw|

15. IrishBoy123

yes, that's what it now looks like.

16. Michele_Laino

namely the points A and B are at the same voltage: |dw:1434539581793:dw|

17. kanwal32

yes

18. Michele_Laino

so the equivalent capacitance is: $\Large {C_{EQUIVALENT}} = {C_1} + \frac{{{C_2}{C_3}}}{{{C_2} + {C_3}}}$

Showing the two leads which indicate an input or the connecting to the associated circuit made all the difference in resolving the configuration.