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kanwal32
 one year ago
Easy capacitance doubt
kanwal32
 one year ago
Easy capacitance doubt

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kanwal32
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434537935776:dw

kanwal32
 one year ago
Best ResponseYou've already chosen the best response.0what will be the equivalent capacitance and why we will take the two in series @Michele_Laino

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0confused. is this not 3 in series or is circuit incomplete?

kanwal32
 one year ago
Best ResponseYou've already chosen the best response.0are they three in series

kanwal32
 one year ago
Best ResponseYou've already chosen the best response.0should i give any other example to clear my doubt

kanwal32
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434539076748:dw

kanwal32
 one year ago
Best ResponseYou've already chosen the best response.0why 2 and 3 are in series and not 1 and 2

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0the draw function seems to have disappeared from the user interface. i can't draw anymore.

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1since we can rewrite your circuit as follows: dw:1434539474858:dw

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0yes, that's what it now looks like.

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1namely the points A and B are at the same voltage: dw:1434539581793:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so the equivalent capacitance is: \[\Large {C_{EQUIVALENT}} = {C_1} + \frac{{{C_2}{C_3}}}{{{C_2} + {C_3}}}\]

radar
 one year ago
Best ResponseYou've already chosen the best response.1Showing the two leads which indicate an input or the connecting to the associated circuit made all the difference in resolving the configuration.
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