## mathmath333 one year ago find the $$\large 1031^{th}$$ term of the sequence.

1. mathmath333

\large \color{black}{\begin{align} 1,\ 2,\ 2,\ 4,\ 4,\ 4,\ 4,\ 8,\ 8,\ 8,\ 8,\ 8,\ 8,\ 8,\ 8,\cdots \ \infty +\hspace{.33em}\\~\\ \end{align}}

2. mathmate

You have already shown: 1st term=1 3rd term=2 7th term=4 15th term=8 ... can you find the 1023rd term? and hence the 1031st term?

3. mathmath333

no i didnt understand

4. kanwal32

1024

5. kanwal32

or 512

6. mathmate

In case you haven't found it yet: 1st term=$$2^1-1$$ st term=1 =$$2^0$$ 3rd term=$$2^2-1$$ rd term=2=$$2^1$$ 7th term=$$2^3-1$$ th term=4=$$2^2$$ 15th term=$$2^4-1$$ th term=8=$$2^3$$ ... can you find the 1023rd term? =$$2^{10}-1$$ rd term = $$2^9$$ = 512 and hence the 1031st term?

7. mathmath333

is it 1024

8. mathmate

Yes, the next one is 1024! In fact, the 1024th term starts at 1024, etc.