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mathmath333
 one year ago
find the \(\large 1031^{th}\) term of the sequence.
mathmath333
 one year ago
find the \(\large 1031^{th}\) term of the sequence.

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align} 1,\ 2,\ 2,\ 4,\ 4,\ 4,\ 4,\ 8,\ 8,\ 8,\ 8,\ 8,\ 8,\ 8,\ 8,\cdots \ \infty +\hspace{.33em}\\~\\ \end{align}}\)

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1You have already shown: 1st term=1 3rd term=2 7th term=4 15th term=8 ... can you find the 1023rd term? and hence the 1031st term?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0no i didnt understand

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1In case you haven't found it yet: 1st term=\(2^11\) st term=1 =\(2^0\) 3rd term=\(2^21\) rd term=2=\(2^1\) 7th term=\(2^31\) th term=4=\(2^2\) 15th term=\(2^41\) th term=8=\(2^3\) ... can you find the 1023rd term? =\(2^{10}1\) rd term = \(2^9\) = 512 and hence the 1031st term?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Yes, the next one is 1024! In fact, the 1024th term starts at 1024, etc.
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