anonymous
  • anonymous
HELP ME?? IM NOT GOOD WITH Graphing Piecewise Functions WILL MEDAL AND FAN
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
alright so according to what I understand, you have 2 equations that you need to find, and put those 2 equations in their right boxes according to their range, for the line at y=5 , since the line passes through the y-axis when y=5, the line is then simply y=5, or f(x) = 5 is you will, now look at the point at which the line starts and read off the x value at this point, and look at the point at which the line ends and read off the x-value at this point, you will see that x=-1 at the point where the line starts, and x=1 where the line ends, so meaning that y=5 satisfies the range of x : -1
anonymous
  • anonymous
so now the other line is def satisfying the other x range, this line is a little more complicated, you have to construct an equation in the form y=mx+c , where m is your gradient of the slope , and c is the y-intercept, or the point at which the touches the y-axis to find the m, you need to find 2 coordinates first, ill use the point at which the line crosses the x-axis at (-3,0) and a point above it that also lies on the line -> (-2, 1) to find m , you use the formula : |dw:1434557381435:dw| so taking the point (-2,1) as x2 and y2, and (-3,0) as x1 and y1, you substitute and find the m

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
so try substituting and ill tell you if it's wrong :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.