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alright so according to what I understand, you have 2 equations that you need to find, and put those 2 equations in their right boxes according to their range, for the line at y=5 , since the line passes through the y-axis when y=5, the line is then simply y=5, or f(x) = 5 is you will, now look at the point at which the line starts and read off the x value at this point, and look at the point at which the line ends and read off the x-value at this point, you will see that x=-1 at the point where the line starts, and x=1 where the line ends, so meaning that y=5 satisfies the range of x : -1
so now the other line is def satisfying the other x range, this line is a little more complicated, you have to construct an equation in the form y=mx+c , where m is your gradient of the slope , and c is the y-intercept, or the point at which the touches the y-axis to find the m, you need to find 2 coordinates first, ill use the point at which the line crosses the x-axis at (-3,0) and a point above it that also lies on the line -> (-2, 1) to find m , you use the formula : |dw:1434557381435:dw| so taking the point (-2,1) as x2 and y2, and (-3,0) as x1 and y1, you substitute and find the m
so try substituting and ill tell you if it's wrong :)