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anonymous

  • one year ago

Check my answers? 6. simplify x / 7x+x^2 --> 1/7+x where x/= 0,-7 7. simplify -14x^3 / x^3-5x^4 --> -14/1-5x where x /= 1/5, 0 8. x-2 / x^2+4x-12 --> 1/x+6 where x/= -6, 2 9.x^2-3x-10 dont know yet 10. 2/3a * 2/a^2 dont know yet 11. x+2/5x-15 * (10x^2-25x-15) --> (2x+1)/5(x-3) 12. (x^2-16/x-1) dont know yet

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  1. anonymous
    • one year ago
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    for 6-> it would be 1/7 + x^2

  2. anonymous
    • one year ago
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    thats not one of the choices

  3. anonymous
    • one year ago
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    are you sure? because there's no way that x^2 can be simplified to x without cancelling which cant be done because you've already cancelled out the x 's from x/7x

  4. anonymous
    • one year ago
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    7 and 8 are right btw

  5. anonymous
    • one year ago
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    yes the choices are 1/7+x; where x/= -7 1/7x; where x/= 0 1/7+x where x/= 0,-7 1/7

  6. anonymous
    • one year ago
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    for 9, the answer would be simply be (x-5)(x+2) because you just split it up, and 10 : \[\frac{ 2 }{ 3a }*\frac{ 2 }{ a^2 }\] =4/3a^3 when you multiply the numerators and the denominator together

  7. anonymous
    • one year ago
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    for #9, thats not a choice but there is x-5; where x /=-2 ??

  8. anonymous
    • one year ago
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    ya, that's also correct

  9. anonymous
    • one year ago
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    how about 11 & 12?

  10. anonymous
    • one year ago
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    thanks for your help btw

  11. anonymous
    • one year ago
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    @Purplerainbowcherry

  12. anonymous
    • one year ago
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    I'm not really sure about 12 because all I could simplify it to was (x+4)(x-4)/(x-1)

  13. anonymous
    • one year ago
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    x+4/x-1 ?

  14. anonymous
    • one year ago
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    that's the thing, I dont really get how the functions are suddenly disappearing in your choices, but if thats the answer that's closest then go for it I guess

  15. anonymous
    • one year ago
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    i have no idea either tbh

  16. anonymous
    • one year ago
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    how about this, you choose a value for x and see if you get the same answer for the original function, and for your simplified function

  17. anonymous
    • one year ago
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    did you try what I said?

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spraguer (Moderator)
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