Help me please

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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@Michele_Laino do u think u can help me out?
we have this ratio: \[\frac{{AE}}{{AR}} = \frac{{15}}{{12}} = \frac{5}{4}\]

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or: \[\frac{{AR}}{{AE}} = \frac{{12}}{{15}} = \frac{4}{5}\]
now, we can show that the requested ratio is given by the square of the last ratio, namely: \[\frac{{area\left( {\vartriangle ARH} \right)}}{{area\left( {\vartriangle ARS} \right)}} = {\left( {\frac{{AR}}{{AE}}} \right)^2} = ...?\]
oops.. \[\frac{{area\left( {\vartriangle ARH} \right)}}{{area\left( {\vartriangle AES} \right)}} = {\left( {\frac{{AR}}{{AE}}} \right)^2} = ...?\]
what is the right option?

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