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anonymous

  • one year ago

What is ^2√(-125) ?

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  1. anonymous
    • one year ago
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    \[\sqrt[2]{-125}\] It looks a little more like this XD

  2. anonymous
    • one year ago
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    Are you allowed to use complex numbers?

  3. anonymous
    • one year ago
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    Well i have to be able to write it in decimal form, but i don't know if it will be a decimal.

  4. anonymous
    • one year ago
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    you get me? XD

  5. anonymous
    • one year ago
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    yes you can write it as $$ \sqrt {-125} = \a $$

  6. perl
    • one year ago
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    \[ \sqrt {-125} = \sqrt{-1} \cdot \sqrt{125}= i ~ \sqrt{125} \]

  7. anonymous
    • one year ago
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    i don't thunk I'm cetching on..

  8. perl
    • one year ago
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    \[ \sqrt {-125} = \sqrt{-1} \cdot \sqrt{125}= i ~ \sqrt{125}\\ = i ~ 11.1803 \]

  9. anonymous
    • one year ago
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    Yeah i think thats what the question wants XD

  10. anonymous
    • one year ago
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    So the answer is 11.1803?

  11. perl
    • one year ago
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    11.1803i , but it is an approximation

  12. anonymous
    • one year ago
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    ok thankyou!

  13. anonymous
    • one year ago
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    oh apperently it has to be a two digget number.. it could be like .12, 1.2, or 12 im not sure XD

  14. perl
    • one year ago
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    can you take a screenshot of the question, I might have missed something

  15. anonymous
    • one year ago
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    i cant, im using my computer. But the question just says "What is \[\sqrt[2]{-125}\] ?"

  16. anonymous
    • one year ago
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    \[\sqrt[2]{-125}\] oops i guess it didnt go into equation form

  17. perl
    • one year ago
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    the simplified exact solution is \[ \Large 5 \sqrt 5~ i \] the approximate solution is \( \large 11.2i \)

  18. anonymous
    • one year ago
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    hm.. so should i just round and say the answer is 11?

  19. perl
    • one year ago
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    The directions don't say to round though...

  20. anonymous
    • one year ago
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    no all they ask is for the answer XD

  21. perl
    • one year ago
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    the exact answer is preferable

  22. anonymous
    • one year ago
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    yeah but i can only have two numbers.. heh i dont know XD im just going to put 11

  23. anonymous
    • one year ago
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    do you mind helping me with 1 more?

  24. perl
    • one year ago
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    ok

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