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anonymous
 one year ago
Solve on the interval [0,2π):
4 csc x+1 = 3
A. 2π/3, 4π/3
B. π/6, 5π/6
C. 3π/2
D. 7π/6, 11π/6
***My Answer: B***
Not too sure though. Please help!
anonymous
 one year ago
Solve on the interval [0,2π): 4 csc x+1 = 3 A. 2π/3, 4π/3 B. π/6, 5π/6 C. 3π/2 D. 7π/6, 11π/6 ***My Answer: B*** Not too sure though. Please help!

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well first subtract the 1 from the first side to get 4 csc x = 4 and then divide each side by 4 to get csc x = 1, then you know that csc x = 1/sin x so (1/sin x)=1. If you simplify this algebraically it is sin x = 1 which is true only at 3pi/2, therefore you are correct.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Great! Thank you so much!
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