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anonymous
 one year ago
Help for a medal???
anonymous
 one year ago
Help for a medal???

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Charlie needs to simplify the expression below before he substitutes values for x and y. If x ≠ 0 and y ≠ 0, which of the following is a simplified version of the expression below? x^9y^5 x^24y^16 x^6y^3 + x^3y^2 x^15y^8 + x^6y^4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@zepdrix Can you help?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large\rm \frac{x^{18}y^{12}+x^9y^8}{x^3y^4}\]So um... we have three x's multiplying in the bottom. We'd like to find three x's in the top also, so we can cancel some stuff out. But to do that we need to take the x's out of each term in the top. Do you remember how to factor? :) How do we take three x's out of each term in the top?\[\Large\rm x^{18}y^{12}+x^9y^8=x^3(\quad ?\quad+\quad?\quad)\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Hannah Bananaaaaa +_+ where you at girrrrrr

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry D: Pizza comes first math comes second! Do I add the Xs together?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Ooo pizza noice :U no. You're dividing some x's out of each term.dw:1434569099407:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So would you divide x^3 by x^9 and x^18?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright, give me a sec

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1See the first term, you're multiplying 18 x's together. If you pull 3 of them out, then you're only multiplying 15 x's together, ya? I don't think you wanted to divide the 18 by 3 silly :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oooooooooooooooooooohhhhhh. Alright, gotcha!

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1So let's see what pulling out the x^3 does for us:\[\Large\rm \frac{x^{18}y^{12}+x^9y^8}{x^3y^4}=\frac{\color{orangered}{x^3}(x^{15}y^{12}+x^3y^{8})}{\color{orangered}{x^3}y^4}\]Ooo notice now that we have some matching x's on top and bottom! So we can cancel out that junk.\[\Large\rm \frac{\cancel{\color{orangered}{x^3}}(x^{15}y^{12}+x^3y^{8})}{\cancel{\color{orangered}{x^3}}y^4}=\frac{x^{15}y^{12}+x^3y^8}{y^4}\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1We'll have to do a similar step to deal with the y's.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Any confusion on that step Bananz? :o You have pizza in your hand don't you _ lol

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1prolly cheese everywhere _

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Since we have y^4 in the bottom, we'd like to try and pull out y^4 from each term in top.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Haha pizza is my life :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait, what do you mean pull the y^4 out? Do you just get rid of it? Or do you gotta divide the y^4 by other Y's?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Or is it something else?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1yes, divide the other y's by y^4.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(x ^{15} y ^{3} + x^3 y^2) = x ^{15} y^{3} + x^3 y^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That took a LONG TIME to type using the equation thing.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1woops! you did it again silly. when you divide y's like that, you need to `subtract` the exponents.\[\Large\rm \frac{y^{12}}{y^4}=y^{124}=y^8\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright, I'll do it again

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(x^{15} y^{12} +x^3 y^{4}) = x^{15} y^{8} + x^3 y^4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OMG I FORGOT ABOUT THE y^12

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This has proved difficult doing while eating pizza

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1careful the way you're writing that +_+ don't forget about the y^4 out front.\[\Large\rm (x^{15} y^{12} +x^3 y^{4}) = \color{orangered}{y^4}(x^{15} y^{8} + x^3 y^4)\]Your work looks correct though :)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large\rm \frac{x^{15}y^{12}+x^3y^8}{y^4}=\frac{\color{orangered}{y^4}(x^{15}y^{8} + x^3y^4)}{\color{orangered}{y^4}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Haha, sorry about that XD

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Cool, so do you see which option you'll end up with? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I dedicate this song to you https://www.youtube.com/watch?v=TjcOJmoJwpk skip to the 0:26 second mark please

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know cliche :D But still, thank you!
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