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anonymous
 one year ago
PLEASE HELP ME UNDERSTAND
Solve for x: 3x − 3 + 2 = 14
No solutions
x = −1, x = 8.3
x = 0, x = 7
x = −1, x = 7
anonymous
 one year ago
PLEASE HELP ME UNDERSTAND Solve for x: 3x − 3 + 2 = 14 No solutions x = −1, x = 8.3 x = 0, x = 7 x = −1, x = 7

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First step is to get everything but the absolutes alone. So get everything but \(\left x3 \right\) to the other side.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0One more after that, but yes.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right! So we'll be left with \[\large \left x3 \right = 4\] Now to get the absolutes, you get the negative and positive. So we can split it to look like \[\large x3=4~~~and~~~x3=4\] Now solve them :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0add 3 in both equations, but one equation has no solution right, since the absolute valuse cant be negative?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No the x will be negative, the absolute will cancel it out though :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well plug those two in and see if they work.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0poitive 1 doesnt work??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'll show you what went wrong. \[\large x3=4\to \large x=4+3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Correct! Good job :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile \]
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