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anonymous

  • one year ago

PLEASE HELP ME UNDERSTAND Solve for x: 3|x − 3| + 2 = 14 No solutions x = −1, x = 8.3 x = 0, x = 7 x = −1, x = 7

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  1. anonymous
    • one year ago
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    First step is to get everything but the absolutes alone. So get everything but \(\left| x-3 \right|\) to the other side.

  2. anonymous
    • one year ago
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    so subtract 2?

  3. anonymous
    • one year ago
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    One more after that, but yes.

  4. anonymous
    • one year ago
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    then divide by 3

  5. anonymous
    • one year ago
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    Right! So we'll be left with \[\large \left| x-3 \right| = 4\] Now to get the absolutes, you get the negative and positive. So we can split it to look like \[\large x-3=4~~~and~~~x-3=-4\] Now solve them :)

  6. anonymous
    • one year ago
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    add 3 in both equations, but one equation has no solution right, since the absolute valuse cant be negative?

  7. anonymous
    • one year ago
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    No the x will be negative, the absolute will cancel it out though :)

  8. anonymous
    • one year ago
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    ohk?

  9. anonymous
    • one year ago
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    so x=1 or x=-1

  10. anonymous
    • one year ago
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    Well plug those two in and see if they work.

  11. anonymous
    • one year ago
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    they dont

  12. anonymous
    • one year ago
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    Both, or just one?

  13. anonymous
    • one year ago
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    just one

  14. anonymous
    • one year ago
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    poitive 1 doesnt work??

  15. anonymous
    • one year ago
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    I'll show you what went wrong. \[\large x-3=4\to \large x=4+3\]

  16. anonymous
    • one year ago
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    ohk

  17. anonymous
    • one year ago
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    so x=-1 or x=7

  18. anonymous
    • one year ago
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    Correct! Good job :)

  19. anonymous
    • one year ago
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    thanks! :)

  20. anonymous
    • one year ago
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    \[\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile \]

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