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anonymous

  • one year ago

Two quadratic functions are shown. Function 1: f(x) = 2x2 − 8x + 1 Function 2: x g(x) −2 2 −1 −3 0 2 1 17 Which function has the least minimum value and what are its coordinates? Function 1 has the least minimum value and its coordinates are (0, 1). Function 1 has the least minimum value and its coordinates are (2, −7). Function 2 has the least minimum value and its coordinates are (0, 2). Function 2 has the least minimum value and its coordinates are (−1, −3). WILL FAN AND MEDAL

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  1. anonymous
    • one year ago
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    I'm really more of a visual learner, so what I would do is graph the points given and the equation of the graph and calculate the vertex coordinates afterwards, however, you will not always be given that option in standardized testing. What do you think the correct answer is?

  2. anonymous
    • one year ago
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    Recall that the vertex formula is: x = -b/2a (Then plug in value for all values of x to obtain value y)

  3. anonymous
    • one year ago
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    I think the correct answer might be either A or B. I feel like im doing it wrong

  4. campbell_st
    • one year ago
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    for the 1st equation, find the line of symmetry, the minimum value is on that line it is also the x value on the vertex... \[x = \frac{-b}{2a}\] you have b = -8 and a = 2 so find x, then substitute it into the original equation to find the minimum value hope it helps

  5. campbell_st
    • one year ago
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    for the 2nd function, the minimum value is the smallest y value... so looking at the te table the minimum value is y = -3 so the vertex is (0, -3) then compare this to the answer in the 1st part

  6. anonymous
    • one year ago
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    @Aureyliant was i right??

  7. anonymous
    • one year ago
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    Try following the steps @campbell_st provided :)

  8. anonymous
    • one year ago
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    @campbell_st how do i find x for the first one

  9. campbell_st
    • one year ago
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    ok.... the general from of the quadratic is \[ax^2 + bx + c\] comparing this you your equation you have b = -8 and a = 2 does that make sense..?

  10. anonymous
    • one year ago
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    so would it be c?

  11. campbell_st
    • one year ago
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    no... ignore the choices for the minute so to find x \[x = \frac{-(-8)}{2 \times 2}\] what is the value for x..?

  12. anonymous
    • one year ago
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    2 @campbell_st

  13. campbell_st
    • one year ago
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    great so now substitute it into the equation, this will give the minimum value \[f(2) = 2\times(2)^2 - 8 \times 2 + 1\] what is the value of f(2)

  14. anonymous
    • one year ago
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    -7?

  15. campbell_st
    • one year ago
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    great so the vertex of function 1 is at (2, -7) function 2, reading the table has a minimum value at (1, -3) so which function is further down the y-axis..?

  16. anonymous
    • one year ago
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    function 2

  17. campbell_st
    • one year ago
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    you need to compare the y values.... y = -7 and y = -3

  18. campbell_st
    • one year ago
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    |dw:1434572812211:dw|

  19. campbell_st
    • one year ago
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    its not function 2

  20. campbell_st
    • one year ago
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    and the use the vertex in function 1 as part of the answer

  21. anonymous
    • one year ago
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    thank you!

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