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anonymous
 one year ago
Two quadratic functions are shown.
Function 1:
f(x) = 2x2 − 8x + 1 Function 2:
x g(x)
−2 2
−1 −3
0 2
1 17
Which function has the least minimum value and what are its coordinates?
Function 1 has the least minimum value and its coordinates are (0, 1).
Function 1 has the least minimum value and its coordinates are (2, −7).
Function 2 has the least minimum value and its coordinates are (0, 2).
Function 2 has the least minimum value and its coordinates are (−1, −3).
WILL FAN AND MEDAL
anonymous
 one year ago
Two quadratic functions are shown. Function 1: f(x) = 2x2 − 8x + 1 Function 2: x g(x) −2 2 −1 −3 0 2 1 17 Which function has the least minimum value and what are its coordinates? Function 1 has the least minimum value and its coordinates are (0, 1). Function 1 has the least minimum value and its coordinates are (2, −7). Function 2 has the least minimum value and its coordinates are (0, 2). Function 2 has the least minimum value and its coordinates are (−1, −3). WILL FAN AND MEDAL

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm really more of a visual learner, so what I would do is graph the points given and the equation of the graph and calculate the vertex coordinates afterwards, however, you will not always be given that option in standardized testing. What do you think the correct answer is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Recall that the vertex formula is: x = b/2a (Then plug in value for all values of x to obtain value y)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think the correct answer might be either A or B. I feel like im doing it wrong

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1for the 1st equation, find the line of symmetry, the minimum value is on that line it is also the x value on the vertex... \[x = \frac{b}{2a}\] you have b = 8 and a = 2 so find x, then substitute it into the original equation to find the minimum value hope it helps

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1for the 2nd function, the minimum value is the smallest y value... so looking at the te table the minimum value is y = 3 so the vertex is (0, 3) then compare this to the answer in the 1st part

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Aureyliant was i right??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Try following the steps @campbell_st provided :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@campbell_st how do i find x for the first one

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1ok.... the general from of the quadratic is \[ax^2 + bx + c\] comparing this you your equation you have b = 8 and a = 2 does that make sense..?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1no... ignore the choices for the minute so to find x \[x = \frac{(8)}{2 \times 2}\] what is the value for x..?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1great so now substitute it into the equation, this will give the minimum value \[f(2) = 2\times(2)^2  8 \times 2 + 1\] what is the value of f(2)

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1great so the vertex of function 1 is at (2, 7) function 2, reading the table has a minimum value at (1, 3) so which function is further down the yaxis..?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1you need to compare the y values.... y = 7 and y = 3

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434572812211:dw

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1its not function 2

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1and the use the vertex in function 1 as part of the answer
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