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anonymous
 one year ago
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Find the maximum or minimum of the following quadratic function: y = 2x2 + 4x  1.
A. 1
B. 0
C. 1
D. 4
anonymous
 one year ago
Will medal and fan Find the maximum or minimum of the following quadratic function: y = 2x2 + 4x  1. A. 1 B. 0 C. 1 D. 4

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I assume you mean 2x^2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are you familiar with the quadratic formula?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What you can do here is use the first bit of the quadratic formula (b/2a) which will find you the x value of the vertex. Then you simply plug that x value back into your original equation to find the y value of the max / min. Since this function starts with 2, you know that it opens downwards so you will be finding a maximum.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(b/2a) or (4/4) = (1). This is the x value of the maximum. Plugging this back into the equation... 2(1)^2 + 4(1)  1 = 2(1)  4  1 = 2  4  1 or 7. Therefore we know the y value of the maximum is at 7. Seeing as 7 isn't one of your answers, I'm going to assume that the question simply wants you to find the x value of the maximum  that is, only do the first bit of all of this. :) Hope I helped!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer would be 1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, it looks as though the answer would be 1. The question is slightly ambiguous in its wording, but since this function has a maximum at (1,7), 1 is the only coordinate that has a matching answer.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you for helping me
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