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mathmath333
 one year ago
Fun question
mathmath333
 one year ago
Fun question

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align} & \normalsize \text{Let }\ a,b,c \ \normalsize \text{be positive integers such that} \hspace{.33em}\\~\\ & \dfrac{b}{a}\ \normalsize \text{is an integer }\hspace{.33em}\\~\\ & \normalsize \text{if } \ a,b,c \ \ \normalsize \text{are in geometric progression. } \hspace{.33em}\\~\\ & \normalsize \text{and the arithmetic mean of } \ a,b,c \ \ \normalsize \text{is}\ \ (b+2) \hspace{.33em}\\~\\ & \normalsize \text{then find the value of }\ \left(\dfrac{a^2+a14}{a+1} \right)\hspace{.33em}\\~\\ \end{align}}\)

Afrodiddle
 one year ago
Best ResponseYou've already chosen the best response.2It doesn't look fun

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0correct, how u got that

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.5b/a = r(integer) a=a b=ar c=ar^2 (a+ar+ar^2)/3 = ar+2 solving we get  r^2 + r(2)+(16/r) = 0 solve for r we get ( 2 + (44+24/a)^(1/2))/2 1+ 1/2(24/a)^(1/2) well r = integer therefore 24/a = perfect square therefore a=6 we need to find (a^2 + a14)/(a+1) plug a = 6 and get answer = 4

Isaiah.Feynman
 one year ago
Best ResponseYou've already chosen the best response.0I solved it halfway in my head.
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