Fiestaaaaaaa

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Fiestaaaaaaa

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|dw:1434578055256:dw| @pooja195
oh you're offline :) lemme know when you're back maybe we can work on some problems or something

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o-o
@pooja195 study time pooj? :d
yesh! http://prntscr.com/7iogyt
Number 16: \(\Large\rm \overline{RT}=3\) you understand this distance, yes or no? Just count the boxes.
O_oboxes are cut
Not by the straight up and down line, that one isn't cutting them at all, is it? :o
|dw:1434684711240:dw|
oh ok
Unfortunately we won't be able to use that nice trick on slanted lines :)
|dw:1434684805112:dw|
In order to use our distance formula, we'll need the coordinates of each point. I labeled T so far, we go 2 to the right, and 1 up, to get to T. Can you figure out the points for R and S?
zeppy we need to do the ones in the red boxes ._.
o hehe
-.-
|dw:1434685129487:dw|
Hard to read the letter, that's a Q, right? :o Not an O.
its fine :)
\(\Large\rm \overline{MQ}=?\) Do the easier ones first. Don't need the distance formula for this. How long is that line? :O
3
|dw:1434685342659:dw|Mmm k good. We can this nice shortcut with QP also, ya?
Now we need some coordinate points.
gimme :O
(3,2) <--N (2,-2) <---P
\[\Large\rm N(\color{orangered}{3},\color{royalblue}{2}),\qquad P(\color{red}{2},\color{blue}{-2})\]So using our distance formula, \[\Large\rm \overline{NP}=\sqrt{(\color{red}{x_2}-\color{orangered}{x_1})^2+(\color{blue}{y_2}-\color{royalblue}{y_1})^2}\]\[\Large\rm \overline{NP}=\sqrt{(\color{red}{2}-\color{orangered}{3})^2+(\color{blue}{-2}-\color{royalblue}{2})^2}\]Understand how I plugged those in? :o
im confused .-.
do you remember Pythagorean theorem?
yes
That's really all the distance formula is.
O_O really??
|dw:1434685941480:dw|We're taking this triangle, and we're trying to figure out the hypotenuse length.