Empty
  • Empty
Quick question, what does this mean
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Empty
  • Empty
\[ \mathbb{Z} /n \mathbb{Z} \]
anonymous
  • anonymous
Maybe this will help idk lol https://answers.yahoo.com/question/index?qid=20101008044808AAIoNtG
anonymous
  • anonymous
WAIT This will help http://www3.nd.edu/~sevens/znzstar.pdf

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Empty
  • Empty
Cool that was it thanks.
anonymous
  • anonymous
Yw
anonymous
  • anonymous
(Z/nZ)* is a multiplicative group and is only part of the picture of Z/nZ which typically represents a *ring* Z/nZ (and for prime n you get finite fields since you no longer have to worry about zero-divisors)
anonymous
  • anonymous
it's basically the ring of integers modulo \(n\) with usual addition, multiplication
anonymous
  • anonymous
the notation is suggestive of the fact that \(n\mathbb{Z}\) is an ideal of \(\mathbb{Z}\) and the ring \(\mathbb{Z}/n\mathbb{Z}\) is a quotient (namely of \(\mathbb{Z}\) mod \(n\mathbb{Z}\))

Looking for something else?

Not the answer you are looking for? Search for more explanations.