anonymous
  • anonymous
Patty's Pet Company charges $0.55 per pound to ship pet supplies. Part A: Write an equation to determine the total cost, c, to ship p pounds of pet supplies. Use your equation to determine the cost of shipping 2 pounds of pet supplies. Part B: If the company reduces the cost to ship pet supplies by 0.05 per pound, write an equation to determine the total cost, c, to ship p pounds of pet supplies with the reduced cost
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
can i get help plz
anonymous
  • anonymous
Can I get step by step help
anonymous
  • anonymous
@jim_thompson5910 can you help me

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jim_thompson5910
  • jim_thompson5910
"Patty's Pet Company charges $0.55 per pound to ship pet supplies." how much does it cost to ship exactly 1 pound of pet supplies?
anonymous
  • anonymous
.26
jim_thompson5910
  • jim_thompson5910
how are you getting that?
anonymous
  • anonymous
.55/2
jim_thompson5910
  • jim_thompson5910
"$0.55 per pound" means "$0.55 for each pound" or "$0.55 for one pound"
anonymous
  • anonymous
.55*2 =1.10
jim_thompson5910
  • jim_thompson5910
1 pound simply costs $0.55 you're overthinking
anonymous
  • anonymous
ok
jim_thompson5910
  • jim_thompson5910
how about 7 pounds? how much does that cost?
anonymous
  • anonymous
3.85
jim_thompson5910
  • jim_thompson5910
and how did you get that?
anonymous
  • anonymous
.55*7
jim_thompson5910
  • jim_thompson5910
so in general, if we don't know the amount of pounds, we can just say it's p so the general cost is 0.55*p agreed?
anonymous
  • anonymous
yes
jim_thompson5910
  • jim_thompson5910
so that's why the cost equation is c = 0.55*p
jim_thompson5910
  • jim_thompson5910
"Use your equation to determine the cost of shipping 2 pounds of pet supplies. " now plug in p = 2 into that cost equation
anonymous
  • anonymous
c=.55*2 = 1.10
jim_thompson5910
  • jim_thompson5910
correct
anonymous
  • anonymous
Part B would be c = .50*2?
jim_thompson5910
  • jim_thompson5910
close
jim_thompson5910
  • jim_thompson5910
they say nothing about p being 2 though
anonymous
  • anonymous
c=.50*p
jim_thompson5910
  • jim_thompson5910
correct
anonymous
  • anonymous
Don't i need to work it out are just leave it as the equation ?
anonymous
  • anonymous
.50*1.10?
jim_thompson5910
  • jim_thompson5910
they just want c = 0.50p for part B
anonymous
  • anonymous
got it thanks
jim_thompson5910
  • jim_thompson5910
no problem

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