The equation below shows the area of a trapezoid, A, with a height of 9 cm, and one base 35 cm. : A = 9 over 2(b + 35) Which of the following formulas correctly solves for the other base, b? b = 2A over 9 + 35 b = 2 multiplied by A over 9 - 35 b = 2 multiplied by A plus 35, all over 9 b = 2 multiplied by A minus 35, all over 9

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The equation below shows the area of a trapezoid, A, with a height of 9 cm, and one base 35 cm. : A = 9 over 2(b + 35) Which of the following formulas correctly solves for the other base, b? b = 2A over 9 + 35 b = 2 multiplied by A over 9 - 35 b = 2 multiplied by A plus 35, all over 9 b = 2 multiplied by A minus 35, all over 9

Mathematics
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\(A=\dfrac{9}{2(b+35)}\) ?
A=9/2 (b+35)
\[A=\dfrac{9}{2}(b+35)\]?
Yes
multipply both sides by \(\dfrac{2}{9}\) and what do you have?
multiply*
9/2b+ 315/1
2/9b
\((\dfrac{2}{9})A=(\dfrac{\cancel{2}}{\cancel{9}})\dfrac{\cancel{9}}{\cancel{2}}(b+35)\\\dfrac{2}{9}A=b+35\)
you with me?
Yes
subtract 35 from both sides
Hello
so leaving off with what zzrocker said we are solving for b and the last step he did was \[(\dfrac{2}{9})A=(\dfrac{\cancel{2}}{\cancel{9}})\dfrac{\cancel{9}}{\cancel{2}}(b+35)\\\dfrac{2}{9}A=b+35 \]
there's not that much left to do with this problem... if we want b by itself, what do we have to do?
-35
from each side
yes
\[\frac{2}{9}A - 35 = b\] that's it :)
you're looking for this selection right? b = 2 multiplied by A over 9 - 35
thanks @UsukiDoll
can I get a medal? :)
i just did
thank you :)

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