anonymous
  • anonymous
The equation below shows the area of a trapezoid, A, with a height of 9 cm, and one base 35 cm. : A = 9 over 2(b + 35) Which of the following formulas correctly solves for the other base, b? b = 2A over 9 + 35 b = 2 multiplied by A over 9 - 35 b = 2 multiplied by A plus 35, all over 9 b = 2 multiplied by A minus 35, all over 9
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@zzr0ck3r
anonymous
  • anonymous
can you help
anonymous
  • anonymous
@wio

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More answers

zzr0ck3r
  • zzr0ck3r
\(A=\dfrac{9}{2(b+35)}\) ?
anonymous
  • anonymous
A=9/2 (b+35)
zzr0ck3r
  • zzr0ck3r
\[A=\dfrac{9}{2}(b+35)\]?
anonymous
  • anonymous
Yes
zzr0ck3r
  • zzr0ck3r
multipply both sides by \(\dfrac{2}{9}\) and what do you have?
zzr0ck3r
  • zzr0ck3r
multiply*
anonymous
  • anonymous
9/2b+ 315/1
anonymous
  • anonymous
2/9b
zzr0ck3r
  • zzr0ck3r
\((\dfrac{2}{9})A=(\dfrac{\cancel{2}}{\cancel{9}})\dfrac{\cancel{9}}{\cancel{2}}(b+35)\\\dfrac{2}{9}A=b+35\)
zzr0ck3r
  • zzr0ck3r
you with me?
anonymous
  • anonymous
Yes
zzr0ck3r
  • zzr0ck3r
subtract 35 from both sides
anonymous
  • anonymous
@skullpatrol
anonymous
  • anonymous
@wio
anonymous
  • anonymous
@UsukiDoll
anonymous
  • anonymous
@freckles
anonymous
  • anonymous
Hello
UsukiDoll
  • UsukiDoll
so leaving off with what zzrocker said we are solving for b and the last step he did was \[(\dfrac{2}{9})A=(\dfrac{\cancel{2}}{\cancel{9}})\dfrac{\cancel{9}}{\cancel{2}}(b+35)\\\dfrac{2}{9}A=b+35 \]
UsukiDoll
  • UsukiDoll
there's not that much left to do with this problem... if we want b by itself, what do we have to do?
anonymous
  • anonymous
-35
anonymous
  • anonymous
from each side
UsukiDoll
  • UsukiDoll
yes
UsukiDoll
  • UsukiDoll
\[\frac{2}{9}A - 35 = b\] that's it :)
UsukiDoll
  • UsukiDoll
you're looking for this selection right? b = 2 multiplied by A over 9 - 35
anonymous
  • anonymous
thanks @UsukiDoll
UsukiDoll
  • UsukiDoll
can I get a medal? :)
anonymous
  • anonymous
i just did
UsukiDoll
  • UsukiDoll
thank you :)

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