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anonymous

  • one year ago

Can someone help for a medal?

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  1. anonymous
    • one year ago
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    A greenhouse that specializes in growing geraniums is divided into sections. The number of geranium pots in each section depends on the number of sprinklers in that section. There are x(7x − 2) pots of red geraniums and (x + 3)2 pots of pink geraniums in a section with x sprinklers. Which simplified expression represents the total number of red and pink geranium pots in a section with x sprinklers? 8x2 + 4x + 9 8x2 + 6x + 9 8x2 + 6x + 7 8x4 + 4x2 + 9

  2. Plasmataco
    • one year ago
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    ok

  3. Plasmataco
    • one year ago
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    graph?

  4. anonymous
    • one year ago
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    Nope, did not come with one :(

  5. Plasmataco
    • one year ago
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    the first one. Im not that sure tho

  6. Plasmataco
    • one year ago
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    yup, the first 1

  7. anonymous
    • one year ago
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    What made you choose the first one?

  8. anonymous
    • one year ago
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    @Plasmataco

  9. anonymous
    • one year ago
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    Is he correct?

  10. jim_thompson5910
    • one year ago
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    what does x*(7x-2) simplify to?

  11. anonymous
    • one year ago
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    7x^2 - 2x

  12. jim_thompson5910
    • one year ago
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    how about (x+3)^2 ?

  13. anonymous
    • one year ago
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    x^2 + 9?

  14. jim_thompson5910
    • one year ago
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    nope

  15. jim_thompson5910
    • one year ago
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    close though

  16. jim_thompson5910
    • one year ago
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    you have to FOIL

  17. jim_thompson5910
    • one year ago
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    \[\Large (a+b)^2 \neq a^2 + b^2\]

  18. jim_thompson5910
    • one year ago
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    \[\Large (a+b)^2 = (a+b)*(a+b)\] then FOIL

  19. anonymous
    • one year ago
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    I never understood how to use FOIL :(

  20. jim_thompson5910
    • one year ago
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    why not try a table then

  21. jim_thompson5910
    • one year ago
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    |dw:1434587606302:dw|

  22. jim_thompson5910
    • one year ago
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    fill out the table by multiplying the headers eg: x times 3 = 3x |dw:1434587643368:dw|

  23. anonymous
    • one year ago
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    Ooh, this method is completely new to me. So would the top left be x^2?

  24. jim_thompson5910
    • one year ago
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    yes since x times x = x^2 |dw:1434587719782:dw|

  25. anonymous
    • one year ago
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    And the bottom left would be 3x

  26. jim_thompson5910
    • one year ago
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    yep |dw:1434587746108:dw|

  27. anonymous
    • one year ago
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    Alright, so what next?

  28. jim_thompson5910
    • one year ago
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    we fill out the last box 3 times 3 = 9 |dw:1434587803197:dw|

  29. anonymous
    • one year ago
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    Oh you do that side too??

  30. jim_thompson5910
    • one year ago
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    then we add up all of the expressions inside the table |dw:1434587822641:dw|

  31. anonymous
    • one year ago
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    Well, box I mean. Haha, sorry about that

  32. jim_thompson5910
    • one year ago
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    yeah the entire table needs to be filled out

  33. anonymous
    • one year ago
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    So x^2 + 6x + 9

  34. jim_thompson5910
    • one year ago
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    very good

  35. jim_thompson5910
    • one year ago
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    so (x+3)^2 = x^2 + 6x + 9

  36. jim_thompson5910
    • one year ago
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    now add 7x^2 - 2x and x^2 + 6x + 9 to get your answer

  37. anonymous
    • one year ago
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    8x^2 + 5x + 9?

  38. jim_thompson5910
    • one year ago
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    close

  39. anonymous
    • one year ago
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    What did I do wrong? Am I supposed to add the exponents? Or...?

  40. jim_thompson5910
    • one year ago
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    line up the terms and add straight down |dw:1434587769859:dw|

  41. jim_thompson5910
    • one year ago
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    the exponents stay the same

  42. jim_thompson5910
    • one year ago
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    \[\Large 7x^2 + x^2 = 8x^2\] \[\Large 7x^2 + x^2 \neq 8x^4\]

  43. anonymous
    • one year ago
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    OH MY GOD I FEEL SO STUPID

  44. anonymous
    • one year ago
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    I messed up simple subtraction...

  45. jim_thompson5910
    • one year ago
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    don't beat yourself up, it's fine

  46. anonymous
    • one year ago
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    7x^2 + 4x + 9. Sorry about that :D

  47. anonymous
    • one year ago
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    8x^2 + 4x + 9*

  48. jim_thompson5910
    • one year ago
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    looks good |dw:1434588029526:dw|

  49. anonymous
    • one year ago
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    Alright, so what do we do from here?

  50. jim_thompson5910
    • one year ago
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    the problem is done now

  51. anonymous
    • one year ago
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    Oh, yeah my bad. I was looking at the wrong question on my sheet. Sorry about that. Thank you so much!

  52. jim_thompson5910
    • one year ago
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    no problem

  53. anonymous
    • one year ago
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    @jim_thompson5910 One more thing. You should really be a qualified helper. You are so good at breaking down the steps to a point where really anyone can understand it. You really should get paid to do help others if you don't already.

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