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Jravenv
 one year ago
Help me please
screencap in comments.
best answer rewarded
Jravenv
 one year ago
Help me please screencap in comments. best answer rewarded

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Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434589442935:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Try it out and see what you get and I will tell you if you're doing it right or not :)

Jravenv
 one year ago
Best ResponseYou've already chosen the best response.0I honestly don't know how to do that, Can you walk me through it? :(

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434589708339:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434589758515:dw can you finish it off...

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You'll have to take the conjugate after to, it's a fun problem :P.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1I will be back in a few minutes, please try it, and if you are stuck don't worry I will help you once I'm back!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is it clear that \[\sqrt 8\times \sqrt 2=\sqrt {16}=4\]

Jravenv
 one year ago
Best ResponseYou've already chosen the best response.0How does the square root of 16=4 though?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because \(4^2=4\times 4=16\) right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0since \(4^2=16\) then \(\sqrt{16}=4\)

Jravenv
 one year ago
Best ResponseYou've already chosen the best response.0Ohh yeah okay, I'm following

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Hey, I'm back, hi satellite :P

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Ok so where are you now, \[4  \sqrt{8}x = 11\] can you collect like terms?

Jravenv
 one year ago
Best ResponseYou've already chosen the best response.0There aren't any are there?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Notice the 4 and 11, so we have \[\sqrt{8}x = 114 \implies \sqrt{8}x = 7\] does that make sense?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Ok now we just divide \[x = \frac{ 7 }{ \sqrt{8} }\] so far so good?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1But if you compare this with your answers, you will notice it's not one of the choices right? That's the tricky part hehe.

Jravenv
 one year ago
Best ResponseYou've already chosen the best response.0Well shucks, what do we got to do?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ 7 }{ \sqrt{8} } \times \frac{ \sqrt{8} }{ \sqrt{8} }\] we have to multiply by sqrt(8) because we can not have the sqrt(8) at the bottom.

Jravenv
 one year ago
Best ResponseYou've already chosen the best response.0I don't know how I would multiply that

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ 7 }{ \sqrt{8} } \times \frac{ \sqrt{8} }{ \sqrt{8} } = \frac{ 7 \sqrt{8} }{ 8 }\] because \[\sqrt{8} \times \sqrt{8} = \sqrt{64} = 8\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Does that all make sense?

Jravenv
 one year ago
Best ResponseYou've already chosen the best response.0Yes sir! Thank you! You were very thorough and patient with me I am very thankful

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You could also simplify it to \[\frac{ 7 \sqrt{2} }{ 4 }\] I think this is what they want
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