Jravenv
  • Jravenv
Help me please screencap in comments. best answer rewarded
Mathematics
jamiebookeater
  • jamiebookeater
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Jravenv
  • Jravenv
Astrophysics
  • Astrophysics
|dw:1434589442935:dw|
Astrophysics
  • Astrophysics
Try it out and see what you get and I will tell you if you're doing it right or not :)

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Jravenv
  • Jravenv
I honestly don't know how to do that, Can you walk me through it? :(
Astrophysics
  • Astrophysics
|dw:1434589708339:dw|
Astrophysics
  • Astrophysics
|dw:1434589758515:dw| can you finish it off...
Astrophysics
  • Astrophysics
You'll have to take the conjugate after to, it's a fun problem :P.
Astrophysics
  • Astrophysics
I will be back in a few minutes, please try it, and if you are stuck don't worry I will help you once I'm back!
Jravenv
  • Jravenv
I don't get it :/
anonymous
  • anonymous
is it clear that \[\sqrt 8\times \sqrt 2=\sqrt {16}=4\]
Jravenv
  • Jravenv
How does the square root of 16=4 though?
anonymous
  • anonymous
because \(4^2=4\times 4=16\) right?
anonymous
  • anonymous
since \(4^2=16\) then \(\sqrt{16}=4\)
Jravenv
  • Jravenv
Ohh yeah okay, I'm following
Astrophysics
  • Astrophysics
Hey, I'm back, hi satellite :P
Astrophysics
  • Astrophysics
Ok so where are you now, \[4 - \sqrt{8}x = 11\] can you collect like terms?
Jravenv
  • Jravenv
There aren't any are there?
Astrophysics
  • Astrophysics
Notice the 4 and 11, so we have \[-\sqrt{8}x = 11-4 \implies -\sqrt{8}x = 7\] does that make sense?
Jravenv
  • Jravenv
Yes sir!
Astrophysics
  • Astrophysics
Ok now we just divide \[x = -\frac{ 7 }{ \sqrt{8} }\] so far so good?
Astrophysics
  • Astrophysics
But if you compare this with your answers, you will notice it's not one of the choices right? That's the tricky part hehe.
Jravenv
  • Jravenv
Well shucks, what do we got to do?
Astrophysics
  • Astrophysics
\[-\frac{ 7 }{ \sqrt{8} } \times \frac{ \sqrt{8} }{ \sqrt{8} }\] we have to multiply by sqrt(8) because we can not have the sqrt(8) at the bottom.
Jravenv
  • Jravenv
I don't know how I would multiply that
Astrophysics
  • Astrophysics
\[-\frac{ 7 }{ \sqrt{8} } \times \frac{ \sqrt{8} }{ \sqrt{8} } = -\frac{ 7 \sqrt{8} }{ 8 }\] because \[\sqrt{8} \times \sqrt{8} = \sqrt{64} = 8\]
Astrophysics
  • Astrophysics
:D
Astrophysics
  • Astrophysics
Does that all make sense?
Jravenv
  • Jravenv
Yes sir! Thank you! You were very thorough and patient with me I am very thankful
Astrophysics
  • Astrophysics
Np ^.^
Astrophysics
  • Astrophysics
You could also simplify it to \[-\frac{ 7 \sqrt{2} }{ 4 }\] I think this is what they want

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