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Jravenv

  • one year ago

Help me please screencap in comments. best answer rewarded

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  1. Jravenv
    • one year ago
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  2. Astrophysics
    • one year ago
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    |dw:1434589442935:dw|

  3. Astrophysics
    • one year ago
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    Try it out and see what you get and I will tell you if you're doing it right or not :)

  4. Jravenv
    • one year ago
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    I honestly don't know how to do that, Can you walk me through it? :(

  5. Astrophysics
    • one year ago
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    |dw:1434589708339:dw|

  6. Astrophysics
    • one year ago
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    |dw:1434589758515:dw| can you finish it off...

  7. Astrophysics
    • one year ago
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    You'll have to take the conjugate after to, it's a fun problem :P.

  8. Astrophysics
    • one year ago
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    I will be back in a few minutes, please try it, and if you are stuck don't worry I will help you once I'm back!

  9. Jravenv
    • one year ago
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    I don't get it :/

  10. anonymous
    • one year ago
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    is it clear that \[\sqrt 8\times \sqrt 2=\sqrt {16}=4\]

  11. Jravenv
    • one year ago
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    How does the square root of 16=4 though?

  12. anonymous
    • one year ago
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    because \(4^2=4\times 4=16\) right?

  13. anonymous
    • one year ago
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    since \(4^2=16\) then \(\sqrt{16}=4\)

  14. Jravenv
    • one year ago
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    Ohh yeah okay, I'm following

  15. Astrophysics
    • one year ago
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    Hey, I'm back, hi satellite :P

  16. Astrophysics
    • one year ago
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    Ok so where are you now, \[4 - \sqrt{8}x = 11\] can you collect like terms?

  17. Jravenv
    • one year ago
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    There aren't any are there?

  18. Astrophysics
    • one year ago
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    Notice the 4 and 11, so we have \[-\sqrt{8}x = 11-4 \implies -\sqrt{8}x = 7\] does that make sense?

  19. Jravenv
    • one year ago
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    Yes sir!

  20. Astrophysics
    • one year ago
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    Ok now we just divide \[x = -\frac{ 7 }{ \sqrt{8} }\] so far so good?

  21. Astrophysics
    • one year ago
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    But if you compare this with your answers, you will notice it's not one of the choices right? That's the tricky part hehe.

  22. Jravenv
    • one year ago
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    Well shucks, what do we got to do?

  23. Astrophysics
    • one year ago
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    \[-\frac{ 7 }{ \sqrt{8} } \times \frac{ \sqrt{8} }{ \sqrt{8} }\] we have to multiply by sqrt(8) because we can not have the sqrt(8) at the bottom.

  24. Jravenv
    • one year ago
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    I don't know how I would multiply that

  25. Astrophysics
    • one year ago
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    \[-\frac{ 7 }{ \sqrt{8} } \times \frac{ \sqrt{8} }{ \sqrt{8} } = -\frac{ 7 \sqrt{8} }{ 8 }\] because \[\sqrt{8} \times \sqrt{8} = \sqrt{64} = 8\]

  26. Astrophysics
    • one year ago
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    :D

  27. Astrophysics
    • one year ago
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    Does that all make sense?

  28. Jravenv
    • one year ago
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    Yes sir! Thank you! You were very thorough and patient with me I am very thankful

  29. Astrophysics
    • one year ago
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    Np ^.^

  30. Astrophysics
    • one year ago
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    You could also simplify it to \[-\frac{ 7 \sqrt{2} }{ 4 }\] I think this is what they want

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