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anonymous

  • one year ago

Determine if triangle DEF with coordinates D(2, 1), E(3, 5), and F(6, 2) is an equilateral triangle. Use evidence to support your claim.

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  1. anonymous
    • one year ago
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    @jim_thompson5910 @geekfromthefutur can u please help me ??

  2. jim_thompson5910
    • one year ago
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    You need to prove that DE = EF = DF

  3. jim_thompson5910
    • one year ago
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    To find the length of DE, you find the distance from D to E Use the distance formula \[\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\]

  4. jim_thompson5910
    • one year ago
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    |dw:1434592177602:dw|

  5. anonymous
    • one year ago
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    oh ok give me one second (:

  6. jim_thompson5910
    • one year ago
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    Alright, take all the time you need. I'll be right back

  7. anonymous
    • one year ago
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    ok (:

  8. anonymous
    • one year ago
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    @jim_thompson5910 sorry to bother but im stuck on a part its the coordinates (6,2) im not sure where it would go but i know (2,1) would plug into (x1,x2) and then coordinates (3,5) would plug into (y1,y2) right?

  9. jim_thompson5910
    • one year ago
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    D(2, 1), E(3, 5), let D be the point (x1,y1) let E be the point (x2,y2) so x1 = 2 x2 = 3 y1 = 1 y2 = 5 \[\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\] \[\Large d = \sqrt{\left(3-2\right)^2+\left(5-1\right)^2}\] \[\Large d = \sqrt{\left(1\right)^2+\left(4\right)^2}\] \[\Large d = \sqrt{1+16}\] \[\Large d = \sqrt{17}\] So DE is exactly \(\Large \sqrt{17}\) units long. I'll let you do the other segments EF and DF

  10. jim_thompson5910
    • one year ago
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    I think you meant to use D,E,F instead of A,B,C ?

  11. anonymous
    • one year ago
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    yea sorry (:

  12. jim_thompson5910
    • one year ago
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    You should have \[ DE = \sqrt{17}\\ EF = \sqrt{18}\\ DF = \sqrt{17}\\ \] So it looks like you got it

  13. jim_thompson5910
    • one year ago
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    DE = DF is true but DE = EF is false so not all sides are equal to the same length we don't have an equilateral triangle, but we do have an isosceles triangle

  14. anonymous
    • one year ago
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    oh ok i see what mean (: thank you so much (:

  15. jim_thompson5910
    • one year ago
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    you're welcome

  16. anonymous
    • one year ago
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    @jim_thompson5910 could help me with another Question if u have the chance??

  17. jim_thompson5910
    • one year ago
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    sure, just post where it says 'ask a question' so you have more room and less clutter

  18. anonymous
    • one year ago
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    oh ok (: thank you

  19. jim_thompson5910
    • one year ago
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    np

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