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answer selection A. 4 B. 10 C. 15 D. 30
I got A 2x-3=9 subytract 3 from both sides, then subtract 2. which gives me 4
You are assuming that the triangle is isosceles, which is not given!
You may want to use the properties of centroid to add a few more dimensions to the triangle. Can you do that?
I don't know
Medians divide a side into two equal parts!
by working the problem out could it be any of the other answer selections
Actually, I don't find enough information to solve the problem, but find enough information to eliminate the other choices! |dw:1434595091396:dw|
what other choices
Well, the only recourse I see is that in any triangle, the sum of the two shorter sides must exceed the longest side. Try that with the different options on triangle STX and see if you can eliminate some choices.
Example: St=18, XT=15 For case x=4, 2x-3=11 Since 11+15>18, x=4 is a possible solution.
Can you post the original question as an image?
There is one theorem we could use, which is the six triangles created by the medians all have equal areas. If we assume mSX=3y, mUV=3z, then we can form 3 equations by equating areas of 4 of the six triangles, thus producing 3 equations to solve for x, (y and z). However, the equation of areas using heron's formula end up quite messy, and will require the use of numerical to solve.