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anonymous

  • one year ago

If a 14-foot-diameter sheave is used to drive a cable car, at what angular velocity must sheave turn in order for the cable car to travel 11 miles per hour? Give your answer in revolution per minute.(1 mi = 5280ft)

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  1. anonymous
    • one year ago
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    radius=14/2=7 circumference C=2 pi r \[=2*\frac{ 22 }{ 7 }*7=44ft.\] no .of revolutions in 1 mile \[=\frac{ 5280 }{ 44 }=120\] no. of revolutions in 11 mile=120*11=1320 no. of revolutions in 1 hr.=1320 no. of revolutions per minute=1320/60=?

  2. anonymous
    • one year ago
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    Thanks a lot

  3. anonymous
    • one year ago
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    yw

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