anonymous
  • anonymous
Solve for x: −3|x + 7| = −12 x = 5 over 3, x = −19 over 3 x = −3, x = −11 x = −3, x = 11 No solution
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
First step is to get the absolutes alone. So divide that -3 over to the other side.
anonymous
  • anonymous
\[\left| x \right|=a,x= \pm a\]
anonymous
  • anonymous
\[\left| x-a \right|=b,x-a= \pm b\]

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anonymous
  • anonymous
I keep trying these but I never understand them.
anonymous
  • anonymous
divide by -3 and start with \[|x+7|=4\] then solve \[x+7=4\] and \[x+7=-7\] separately
anonymous
  • anonymous
both are easy to solve, subtract 7 from both sides
anonymous
  • anonymous
dang i meant \[x+7=4\\ x+7=-4\]both are solved by subtracting 7 from both sides
anonymous
  • anonymous
WOW I ACTUALLY GOT IT THANK YOU
anonymous
  • anonymous
Wait I think I got it wrong, I got x = −3, x = 11

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