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anonymous
 one year ago
Help!!
anonymous
 one year ago
Help!!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Solve 10/3x+4/3 = 7+ x/2x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[10/3x+4/3=7+x/2x\] \[20/6x+8x/6x=42x/6x+3x/6x\] \[(20+8x)/6x=45x/6x\] \[120x+48x^2=270x^2\] 222x^2+120x=0 6x(37x+20)=0 x= 20/37

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Let's solve your equation stepbystep. 103x+43=7+x2x Step 1: Simplify both sides of the equation. 103x+43=12x2+7 Step 2: Subtract 1/2x^2+7 from both sides. 103x+43−(12x2+7)=12x2+7−(12x2+7) −12x2+103x+−173=0 Step 3: Use quadratic formula with a=0.5, b=3.3333333333333335, c=5.666666666666667. x=−b±b2−4ac2a x=−(3.3333333333333335)±(3.3333333333333335)2−4(−0.5)(−5.666666666666667)2(−0.5) x=−3.3333333333333335±−0.222222−1 Answer: No real solutions.
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