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Jravenv

  • one year ago

Help me please screencap in comments. best answer rewarded

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  1. Jravenv
    • one year ago
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  2. Isaiah.Feynman
    • one year ago
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    You can subtract the right side from both sides as a start.

  3. Jravenv
    • one year ago
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    wait what?

  4. Isaiah.Feynman
    • one year ago
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    Subtract the term on the right from both sides.

  5. Jravenv
    • one year ago
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    you mean the fraction?

  6. Isaiah.Feynman
    • one year ago
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    Yep. Sorry.

  7. Jravenv
    • one year ago
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    4/n+3

  8. Isaiah.Feynman
    • one year ago
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    No. Rather do a cross multiplication. That's easier.

  9. Isaiah.Feynman
    • one year ago
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    So, \[14(n-4)=10(n+7)\]

  10. Jravenv
    • one year ago
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    Okay, so what's next?

  11. Isaiah.Feynman
    • one year ago
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    Can you solve for n from here?

  12. Jravenv
    • one year ago
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    Um, I'm sorry I don't know how..

  13. Isaiah.Feynman
    • one year ago
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    First we distribute the 14 and the 10 through the parentheses. That gives us... \[14n-56=10n+70\]

  14. Isaiah.Feynman
    • one year ago
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    Do you see a way to solve for n?

  15. Jravenv
    • one year ago
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    Um no I'm sorry! .-.

  16. Isaiah.Feynman
    • one year ago
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    Ever heard of "like terms"?

  17. Jravenv
    • one year ago
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    Yes. you have to combine like terms but every time I look at the equation my mind goes blank, can you help me to break it down a bit more?

  18. Isaiah.Feynman
    • one year ago
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    Okay, well can you combine the like terms? you add the n's separately and the numbers separately.

  19. Jravenv
    • one year ago
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    14+24n?

  20. Isaiah.Feynman
    • one year ago
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    It should be 4n=126. Solve for n from here.

  21. Jravenv
    • one year ago
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    Thank you

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