Jravenv
  • Jravenv
Help me please screencap in comments. best answer rewarded
Mathematics
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Jravenv
  • Jravenv
Help me please screencap in comments. best answer rewarded
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Jravenv
  • Jravenv
Isaiah.Feynman
  • Isaiah.Feynman
You can subtract the right side from both sides as a start.
Jravenv
  • Jravenv
wait what?

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Isaiah.Feynman
  • Isaiah.Feynman
Subtract the term on the right from both sides.
Jravenv
  • Jravenv
you mean the fraction?
Isaiah.Feynman
  • Isaiah.Feynman
Yep. Sorry.
Jravenv
  • Jravenv
4/n+3
Isaiah.Feynman
  • Isaiah.Feynman
No. Rather do a cross multiplication. That's easier.
Isaiah.Feynman
  • Isaiah.Feynman
So, \[14(n-4)=10(n+7)\]
Jravenv
  • Jravenv
Okay, so what's next?
Isaiah.Feynman
  • Isaiah.Feynman
Can you solve for n from here?
Jravenv
  • Jravenv
Um, I'm sorry I don't know how..
Isaiah.Feynman
  • Isaiah.Feynman
First we distribute the 14 and the 10 through the parentheses. That gives us... \[14n-56=10n+70\]
Isaiah.Feynman
  • Isaiah.Feynman
Do you see a way to solve for n?
Jravenv
  • Jravenv
Um no I'm sorry! .-.
Isaiah.Feynman
  • Isaiah.Feynman
Ever heard of "like terms"?
Jravenv
  • Jravenv
Yes. you have to combine like terms but every time I look at the equation my mind goes blank, can you help me to break it down a bit more?
Isaiah.Feynman
  • Isaiah.Feynman
Okay, well can you combine the like terms? you add the n's separately and the numbers separately.
Jravenv
  • Jravenv
14+24n?
Isaiah.Feynman
  • Isaiah.Feynman
It should be 4n=126. Solve for n from here.
Jravenv
  • Jravenv
Thank you

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