Jravenv
  • Jravenv
Help me please screencap in comments. best answer rewarded
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Jravenv
  • Jravenv
anonymous
  • anonymous
1. simplify square roots to simplify the expression more: \[((\sqrt{25}*\sqrt{3a})+(\sqrt{4}*\sqrt{3a})-(\sqrt{9}*\sqrt{3a}))/3a\]
KyanTheDoodle
  • KyanTheDoodle
Probably gonna get banned for saying this, but every time I read your question, I see "best answer retarded"

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anonymous
  • anonymous
2. Next solve the square roots: \[((5*\sqrt{3a})+(2*\sqrt{3a})-(3*\sqrt{3a})/\sqrt{3a}\]
anonymous
  • anonymous
Note: first step denominator should be square root 3a 3. the numerator has like terms so: \[(5+2-3)(\sqrt{3a})/(\sqrt{3a})\rightarrow 5+2-3\rightarrow 4\]
UsukiDoll
  • UsukiDoll
as I mentioned plenty times before...there are different methods to solving the problem in Mathematics as long as it doesn't break the Math rules.
UsukiDoll
  • UsukiDoll
but.. @hughfuve your answer isn't in the choices given... so something is wrong.
UsukiDoll
  • UsukiDoll
because ... (I hope I still remember this right) when you're changing to exponent form \[\sqrt{3a} \rightarrow (3a)^{\frac{1}{2}}\]
UsukiDoll
  • UsukiDoll
you're distributing that 1/2 all over
UsukiDoll
  • UsukiDoll
Ok. I know what's going on.. we need a \[\sqrt{3a}\] in the numerator so we can cancel out the \[\sqrt{3a}\] denominator
UsukiDoll
  • UsukiDoll
so we need to split up 75, 27, and 12
UsukiDoll
  • UsukiDoll
\[\frac{\sqrt{75a}+\sqrt{12a}-\sqrt{27a}}{\sqrt{3a}}\]
UsukiDoll
  • UsukiDoll
ok this is going to work :) we want that denominator to leave but before we have that we need to split up 75, 12, and 27.. we need perfect square numbers
UsukiDoll
  • UsukiDoll
is @Jravenv here right now? I want to guide her through this process we need to know what perfect squares can we use so we can take the square root so what is 3 x ? = 75, 3 x ? = 12, and 3 x ? = 27? there are 3 perfect square numbers
UsukiDoll
  • UsukiDoll
another way is what's 75/3, 12/4 , and 27/3 ???
UsukiDoll
  • UsukiDoll
sorry 75/3, 12/3, and 27/3
Jravenv
  • Jravenv
114/3
UsukiDoll
  • UsukiDoll
this is separate what is 75/3 or 3 x ? = 75
UsukiDoll
  • UsukiDoll
we're not adding those three fractions.. we are using division for 75/3 =? 12/3 =? 27/3 = ?
Jravenv
  • Jravenv
25
UsukiDoll
  • UsukiDoll
yes! so what about 12/3 = ? and 27/3 = ?
Jravenv
  • Jravenv
4 and 8 and a 3rd
UsukiDoll
  • UsukiDoll
what is 12 divided by 3? what is 27 divided by 3?
Jravenv
  • Jravenv
4 and 9
UsukiDoll
  • UsukiDoll
\[\frac{\sqrt{25 \cdot 3 a}+\sqrt{4 \cdot 3a}-\sqrt{9 \cdot 3 a}}{\sqrt{3a}}\]
UsukiDoll
  • UsukiDoll
so all we need is the square root of 25, 4, and 9 what is the square root of 25? what is the square root of 4? what is the square root of 9?
Jravenv
  • Jravenv
5 2 and 3?
UsukiDoll
  • UsukiDoll
yes.
UsukiDoll
  • UsukiDoll
\[\frac{5\sqrt{ 3 a}+2\sqrt{ 3a}-3\sqrt{ 3 a}}{\sqrt{3a}}\]
UsukiDoll
  • UsukiDoll
now we noticed that there is a term in common and I want to factor it out because i want to get rid of the denominator.. so what can we pull out of the numerator?
UsukiDoll
  • UsukiDoll
each term in the numerator has it, so it's safe to factor out :)
UsukiDoll
  • UsukiDoll
I can't factor 5 2 and 3 out, but I can factor _____________?
Jravenv
  • Jravenv
3a
UsukiDoll
  • UsukiDoll
\[\frac{\sqrt{ 3 a}(5+2-3)}{\sqrt{3a}}\] yes notice that now we can get rid of the square root ?
UsukiDoll
  • UsukiDoll
we're left with a very simple equation... using order of operations PEMDAS... well just AS...we just add and subtract.
Jravenv
  • Jravenv
So its 4
UsukiDoll
  • UsukiDoll
yes it's 4. 5+2-3 using order of operations..addition first 5+2 = 7 7-3 (subtraction) 7-3 = 4
anonymous
  • anonymous
geeez I completely forgot how to do that.. you are quite the doll usuki.

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