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MTALHAHASSAN2

  • one year ago

Evaluate to the nearest thousandth. a) 3^2x+5 = 5^6-x

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  1. MTALHAHASSAN2
    • one year ago
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    can someone help me with it

  2. MTALHAHASSAN2
    • one year ago
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    plz

  3. MTALHAHASSAN2
    • one year ago
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    @peachpi

  4. anonymous
    • one year ago
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    This? \[3^{2x+5}=5^{6-x}\]

  5. MTALHAHASSAN2
    • one year ago
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    yes

  6. anonymous
    • one year ago
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    take the natural log (ln) of both sides. Then apply this rule\[\ln a^b=b \ln a\]

  7. MTALHAHASSAN2
    • one year ago
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    what u mean by nature log sorry i forget

  8. anonymous
    • one year ago
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    ln

  9. MTALHAHASSAN2
    • one year ago
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    can you plz show me a bit more

  10. anonymous
    • one year ago
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    this should help you out. http://bosscade.com/c?r=CKUEDE4sd

  11. MTALHAHASSAN2
    • one year ago
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    what is that?

  12. UnkleRhaukus
    • one year ago
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    \[\qquad 3^{2x+5}=5^{6-x}\\ \ln(3^{2x+5})=\ln(5^{6-x})\\\qquad\qquad =\]

  13. UnkleRhaukus
    • one year ago
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    now use the rule above

  14. MTALHAHASSAN2
    • one year ago
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    ok

  15. MTALHAHASSAN2
    • one year ago
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    |dw:1434617821542:dw|

  16. MTALHAHASSAN2
    • one year ago
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    @UnkleRhaukus

  17. UnkleRhaukus
    • one year ago
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    yes ln(3^(2x+5)) = (2x+5) ln (3)

  18. MTALHAHASSAN2
    • one year ago
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    ok so know that I have to do

  19. UnkleRhaukus
    • one year ago
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    what about ln (5^(6-x)) ?

  20. MTALHAHASSAN2
    • one year ago
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    |dw:1434619007344:dw|

  21. anonymous
    • one year ago
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    Hi @MTALHAHASSAN2 can u help me with my question with the discount plz ..you seem like the only one online lol

  22. UnkleRhaukus
    • one year ago
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    so you have : \[\qquad 3^{2x+5}=5^{6-x}\\ \quad \ln(3^{2x+5})=\ln(5^{6-x})\\ (2x+5)\ln (3)=(6-x)\ln(5)\\ \qquad\qquad\qquad = \]

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