so... where would you start with this?
I'm not really sure. I'm not really good at the section I'm currently doing.
that's ok so with a normal parabola (like the below) do you knopw how to get the equation of the line into a form like y = ax^2 + bx + c |dw:1434614183620:dw| (lets pretend thats a curve and my touchpad isn't being moody) ;)
I think so
it s a hyperpola
to determinat the exact equation you have to know the hyperbola formula ; and then compare it to the graph
Can you help me do that please?
sorry my modems being ... interesting...
sorry general form of this type of equation is (x^2/a^2) - (y^2/b^2) = 1
how do I get a and b?
this should help you out http://bosscade.com/c?r=CKUEDE4sd