what is cos b in the triangle

- anonymous

what is cos b in the triangle

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- anonymous

http://static.k12.com/eli/bb/817/-1/0/2_36843_44974/-1/d064582a0cf3fa6c8783e88a968d415900f4a14e/media/6eb300a0cf1356f83a39450126a1321870ef4eca/mediaasset_652569_1.png
b/a
c/b
a/c
c/a

- anonymous

the triangle is not complet

- anonymous

well thats the question .....exactly

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## More answers

- anonymous

the /theta

- anonymous

i hate cos tan and sin ........
worst at it ever

- anonymous

where is you angle degree?

- anonymous

it is very simple

- anonymous

there is none????
@amorfide

- amorfide

sohcahtoa
cos
so we use ah
a is the adjacent side length, h is the hypotenuse so lets draw our triangle
|dw:1434628807787:dw|

- amorfide

hypotenuse is opposite the right angle always

- amorfide

the opposite side length is opposite the angle
and adjacent is the one left over

- amorfide

btw is the question asking cos b
or
cosB

- amorfide

@HWBUSTER00

- amorfide

if it is asking cosB
then
cosB=a/h
lets label our triangle
|dw:1434629018296:dw|
cosB=adjacent/hypotenuse
you can finish it

- MrNood

@amorfide
It must be cos B (and that is the usual way of labelling triangles)
@HWBUSTER00
This is about geometry and is using 'general' notation. You do not need actual numbers (e.g. lengths or angles) to answer the question in 'letters'
The cosB is the adjacent side divided by hypotenuse
each of those sides is denoted by a letter a,b or c
so the answer (as seen ) is a fraction made of letters (such as x/y)
you do not need numbers to answer 'general' equations

- anonymous

WHICH MEANS THAT THE CAPITAL A,B,C are the angles

- anonymous

while the a,b,c are the sides

- anonymous

a/c?

- MrNood

it is 'adjacent divided by hypotenuse'
but you have written
hypotenuse divided by adjacent
just try again - you have the correct sides - in the wrong order

- anonymous

ohhh c/a ......that my fault

- MrNood

OK good
now can I ask you to stop a moment an ask WHY you hate these trig functions?
They are simply divisions (or ratios) of the sides and there are only 3 to remember right now.

- anonymous

they are to complicated ????? I dont know maybee it is because my ocd ???? i hate it when numbers are not there ..........it is so frustrating

- MrNood

|dw:1434629727102:dw|
in these triangles the angle is always the same
If oyu divide the opposite by the adjacent you ALWAYS get the same

- anonymous

2??

- MrNood

In th above case this answer is the TAN of the angle
but the SAME appies to the the ratio between other sides.
If oyu have studied similar triangles you can see why th eratio is always the same

- anonymous

ohh thank you so much!!!!!! you are such a great help.

- anonymous

do you know how to do this on
http://static.k12.com/eli/bb/817/-1/0/2_36843_44974/-1/d064582a0cf3fa6c8783e88a968d415900f4a14e/media/cf27c592a79e2dbe6cffe23d1941dce276408f01/mediaasset_652591_1.png

- MrNood

The actual number is not important - you can see if you keep the angle th esame, but increae the length of a side then the OTHER sides increase by the same scale factor.
THEREFORE the ratio of the sides stays the same provided trh eangle is the same - and those ratios are sine, cosine, and tangent

- anonymous

what is z

- MrNood

I DO know how to do the second one - but it is more important that YOU do
If you look at the angle Z (49 deg) then what is the 'name' of the side z (opposite, adjacent or hypotenuse)
What is the 'name' of the side labelled 4?

- anonymous

adjacent?????leg???

- MrNood

OK - you need to look at the way th etriangles are labelled - once oyu see this then the functions are easier
Look at angle Z
Look at side z
in relation to Angle Z where is side z (opposite, adjacent or hypotenuse)
hint - the hypotenuse is ALWAYS the longest side and is ALWAYS opposite the right angle (90 deg)

- anonymous

opposite

- MrNood

ok good
and now th eside labelled 4?
is that opposite, adjacent or hypotenuse

- anonymous

to what ?? z

- MrNood

in relation to Angle Z where is side labelled 4 (opposite, adjacent or hypotenuse)

- anonymous

adjacent

- MrNood

OK so for angle Z we know
Angle Z= 39 deg
Opposite side = z
Adjacent side = 4
Which of the functions (sin cos and tan) uses Opposite and adjacent?

- MrNood

you must have seen these - there are 3 to remember and there are many ways on the web given to remember them
sine = O/H
cosine = A/H
Tangent = O/A
so which one uses Opposite side and Adjacent side?

- anonymous

sorry i had to go outside .....lol

- anonymous

9.75 or 3.2?

- MrNood

I have no idea what those numbers are
I you want ot understand these functions please answer the above:
sine = O/H
cosine = A/H
Tangent = O/A
so which one uses Opposite side and Adjacent side?
THEN
for angle Z we know
Angle Z= 39 deg
Opposite side = z
Adjacent side = 4

- anonymous

it is a multiple choice question .

- anonymous

3.2
1
39
9.75

- MrNood

I don't really care about the answer - I can do it in my head
I want you to go away not 'hating' trig functions
Do not worry about the numeric answer - concentrate on the method I am showing you.
Please tell me if you are not interested in any of this....and only want the answer

- MrNood

If you want to understand these functions please answer the below:
sine = O/H
cosine = A/H
Tangent = O/A
so which one uses Opposite side and Adjacent side?
THEN
for angle Z we know
Angle Z= 39 deg
Opposite side = z
Adjacent side = 4

- anonymous

so one side of the triangle always less than the other

- MrNood

OK - I'm out of here - I have tried to show oyu the method but you do not seem to want ot follow it.
sine = O/H
cosine = A/H
Tangent = O/A
so which one uses Opposite side and Adjacent side?

- anonymous

z ........but not angle z

- anonymous

my intention was not for you to do my work . it was to help with the question but you decided to give me a whole math lesson for witch I already told you i dont understand. you are being pretty rude and i dont appreciate it. and for some reason you want to take control and i dont know why . it was question .

- MrNood

This a maths forum - I am here to give maths 'help' call it a lesson if oyu want.
I have asked oyu to do a few simple steps which would guide you to the answer and I have tried to expand the concept so that see what oyu are doing is not inherently difficult.
I asked several times for you to answer THIS (below) because it is the next KEY steo to getting the answer you want, but oyu have answered something else, or answered without giving any thought to what I asked.
You have left the forum in th emiddle of help without notice. So I feel it is YOU who is not being polite.
IF you can refer back to what has been discussed and explained in the above posts then you can answer the following:
sine = O/H
cosine = A/H
Tangent = O/A
so which one uses Opposite side and Adjacent side?

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