Find the limit of : ( No L'hopital's rule)

Find the limit of : ( No L'hopital's rule)

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\[\lim_{x \rightarrow \frac{ \pi }{ 6 }} \frac{ 2\sin x -1 }{ \sqrt{3} - 2\cos x }\]

Approaches ( pi/ 6 )

I would use L'hopital's rule

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