anonymous
  • anonymous
Which of the following are binomials? Check all that apply. A. 2 + 3/x B. x^8 C. 2x^4 + x^2 + 1/2 D. x^11 + 1 E. x^2 + 2 F. x^2 + x + 3
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

mathmate
  • mathmate
Hints: To answer this kind of question, we have to understand what a binomial is, and in turn, what makes a "term". The following definitions explain what they are. In algebra, a \(binomial\) is a polynomial which is the sum of two \(terms\), which are monomials. It is the simplest kind of polynomial after the monomials. Examples: 3x+2 is a binomial, 2x is a monomial, x^2+3x+3 is a trinomial, x^3+x^2-2x+3 is a polynomial. In fact, all four examples are also polynomials. A \(term\) is the product of a constant (positive or negative) multiplied by one or more variables raised to a power. For an expression to be a polynomial, the variables of each term must be raised to a non-negative integer power. Examples: -3x^3y^2, +9, 4x^2, 1/x are all terms, but 1/x cannot be part of a polynomial because 1/x = \(x^{-1}\), which is not a positive integer power.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.