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Babynini
 one year ago
Graph and convert this equation to rectangular coordinates
polar equation: r=8cos(theta)
Babynini
 one year ago
Graph and convert this equation to rectangular coordinates polar equation: r=8cos(theta)

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dan815
 one year ago
Best ResponseYou've already chosen the best response.3what do u think an expression for r is? in terms of x and y

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0How did you graph that? o.0

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0em, well I tried multiplying both sides by r and got r^2=8rcos(theta) (x^2+y^2)=8x

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0haha i know that. But i meant how did you come up with that graph.

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0but i think it needs to be simplified further than that. right?

dan815
 one year ago
Best ResponseYou've already chosen the best response.3thats the relationship between polar and cartesian

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0(x^2+y^2)8x = 0 now what?

dan815
 one year ago
Best ResponseYou've already chosen the best response.3u can put it in circle form

dan815
 one year ago
Best ResponseYou've already chosen the best response.3x^2+y^2=8x rewrite it as this first x^28x + y^2=0 ^ complete the square and put the constant on the right side then

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0I don't know how to complete squares :/ that is where I got stuck.

dan815
 one year ago
Best ResponseYou've already chosen the best response.3watch youtube video, its faster

dan815
 one year ago
Best ResponseYou've already chosen the best response.3its going to look like this

dan815
 one year ago
Best ResponseYou've already chosen the best response.3(x4)^216+y^2=0 (x4)^2+y^2=16 (x4)^2+y^2=4^2 radius 4, shift in x by 4

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0hrm ok. I tried looking for a good youtube video but just got all confused =.=

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.0we have the basic formulas  x = rcos(theta) y = rsin(theta) If x^2 + y^2 = r^2 and r^2 = 8rcos(theta) = 8(x) then you have been given that: x^2 + y^2 = 8x x^2 + 8x + y^2 = 0 Convert to the centervertex form for circles.

dan815
 one year ago
Best ResponseYou've already chosen the best response.3um completing square therse nothing to it

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0haha sigh, i know it should be super easy. But not for me xD

dan815
 one year ago
Best ResponseYou've already chosen the best response.3Any quadratic is in the form ax^2+bx+c, where a b and c are anything

dan815
 one year ago
Best ResponseYou've already chosen the best response.3okay no lets change this... to something simpler first

dan815
 one year ago
Best ResponseYou've already chosen the best response.3x^2+bx+c lets say u have an equation of this form

dan815
 one year ago
Best ResponseYou've already chosen the best response.3to put in square form, okay so u need a bracket with the variable + a constant squares

dan815
 one year ago
Best ResponseYou've already chosen the best response.3(x+d)^2 okay when u square this what happens (x+d)(x+d)=x*(x+d) +d*(x+d) = x^2+dx+dx+d^2 = x^2+2dx+d^2 therefore if you want to rewrite x^2+bx+c in (x+d)^2 form then you know that the 2dx has add up to bx 2dx=bx d=b/2 so we see that it has to be in this form (x+b/2)^2 now the constant part will be d^2 or (b/2)^2, this we subtract away as it is in cluded when u square it

dan815
 one year ago
Best ResponseYou've already chosen the best response.3x^2+bx+c > becomes (x+b/2)^2(b/2)^2+c

dan815
 one year ago
Best ResponseYou've already chosen the best response.3in your case we have the equation x^2+bx+c x^28x+0 which means b=8 and c=0 okay so (x+b/2)^2 (b/2)^2+c (x+(8/2))^2  (8/2)^2 +0

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0k..i'm trying to follow hah

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0and then we just put the y^2 back in there?
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