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for the first one plot the graph of x + y = 12 can you do that?
it is easy note that when x = 0 y =12 and when y = 0 x = 12 so plot the point (0,12) and (12,0) and join them up It well be a straight line.
the for x + y <= 12 shade the area below the line
sorry i still dont understand its suppose to \[y=\le2x+3\]
but is the plot 0,12
i described is the plot of x + y <= 12
plot the line 2x + 3 first plot 3 points - they should be in a straight line if youhave done them correctly one point would be when x = 0:- y = 2(0) + 3 = 3 so this point will be (0,3) plot 2 more
what about this one \[y \le2x+3\]
this one will be the areas below the the line y = 2x + 3 - shade it in.
it will look something like this:- |dw:1434652208765:dw|
lol ok but what's the plot it's hard for me to make plots without numbres on the graph
well you cant plot points accurately without numbers on the graph. Haven't you got graph paper?
???? what does 510 mean?
No 5,0 is not a point on the line but it is a point in the shaded area
thats the point 90.3) where the line cuts the y-axis
i thought the other one was 0,3 or is that for both of them
another point would be when x = 1 y = 2(1) + 3 = 5
@dianolove - sorry I can't stay any longer . I've got to go right now.
it's ok ttyl