Gaussian Elimination. Please see attached.

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Gaussian Elimination. Please see attached.

Linear Algebra
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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I am struggling with this and I believe my answer for y and z are correct but I need to solve for x and check this by putting that back into the equation. This is what I am unsure what to do and any help would be much appreciated.
y is wrong
22y -2z = -27

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Other answers:

\( y = \dfrac{-27 +2z}{22}\) , replace \(z = \dfrac{5}{4}\) you will get the correct answer for y , then for x
that = -1.113636
One more thing, you should label how to get the last matrix. I know you use \(2R_1+R_3\), but if you don't state it out, the credit may be took off.
Ok, but should let it as fraction -49/44 , and plug to the first equation to get x
x-4y +z= 5 x = 5 +4y-z dat sit.
thank you
np

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