I am Stuck. Help. MEDAL!!! What is the length of stack H D with bar on top when BH = 20 in., BC = 12 in., and DC = 14 in.? Round your answer to the nearest tenth of an inch. in.

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I am Stuck. Help. MEDAL!!! What is the length of stack H D with bar on top when BH = 20 in., BC = 12 in., and DC = 14 in.? Round your answer to the nearest tenth of an inch. in.

Mathematics
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@Loser66 can you help me.
just the use of Pythatgorean theorem couple of times
@xapproachesinfinity is a perfect guy for this
ok
ok let come from a clearer picture! you recognize HDC is right triangle yes
yes
we are given DC but we need HC to do the so called Pythagoras yes
yes
now what we do is look at the triangle HCB it is also a right triangle and we are given BC and BH so we can find HC
ok how?
so then we have the following:\ HC^2+BC^2=BH^2 HC^2=BH^2-BC^2 HC^2=20^2-12^2
now tell me what is after you take the square root
you have a calculator with right
i got HC=16
me too
now we go back to our first triangle HDC now we have HC=16 and DC=14 we use again that same theorem to find HD HD^2+DC^2=HC^2 HD^2=HC^2-DC^2 HD^2=16^2-14^2
let see what you got
60?
sqrt of 60 not just 60 because i told you to take square root after that too
so then HD=7.75 inch
is that the answer?
if we wanted the decimal, well in a way we want the decimal since we measuring length
yes
can you help me with three more?
let see post in a different section though
ok I will tag you.
ok

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